Gluons are massless so move at the speed of light. Gluons also are supposed to exchange gluons themselves. Wouldn't this require the gluons which are exchanged between gluons to move even faster than light?
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$\begingroup$ Notice the past discussion: physics.stackexchange.com/q/90469/12813 $\endgroup$– wonderichCommented Apr 20, 2018 at 3:16
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There have been good comments to this question, which should be in an answer, because comments have a way of disappearing, so here they are:
For any two particles traveling at the speed of light, unless they're traveling in exactly the same direction, the speed required to intercept one from the other is less than c. – @probably_someone
and another:
Gluons are massless and move at the speed of light. The difference between a photon and gluon is a gluon has a charge of the QCD field, called color. As a result they strongly interact with each other as well as quarks. As a result they are scattered around in a tiny region, sometimes called the QCD bag. At high energy the coupling is reduced and the tend to behave more freely. The gluon then behaves more like a photon moving at the speed of light. Further, gluons most certainly do not move at speeds faster than light. – @Lawrence B. Crowell
And the last,
Your confusion seems to arise due to the misconception that if an object (such as a rocket) moving at the speed of light shoots something out in the direction of its motion then that something must travel faster than light. This is not true. See the relativistic velocity addition formula . @Prahar
The above hold generally in set ups where the velocities are high and special relativity has to be used to calculate numbers. I will address gluons in particular:
Gluons are defined within a mathematical model that describes elementary particle interactions, and exist in the table of particles of the standard model. .
The construction of the standard model is such, that one cannot measure a free gluon the way one can measure a free photon because of the structure of the quantum chromodynamic force, thus there is only the mathematical definition that keeps them within a confined volume generated by the QCD forces.
Gluons are always virtual, which means that the four vector describing them in the feynman diagrams is off mass shell, thus they have a variable mass under the integral which will finally give a prediction for a measurable quantity. Thus it is not meaningful to ask about the off mass shell kinematics within hadrons, which is the only place where gluons have an existence.
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$\begingroup$ If you're planning to add the comments into your answer, it might be a good idea to just go ahead and do it. At some point I'll be deleting those comments. $\endgroup$– David ZCommented Apr 20, 2018 at 5:16
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$\begingroup$ @DavidZ I will give them a day to think about it ? I will alert them $\endgroup$– anna vCommented Apr 20, 2018 at 5:50
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$\begingroup$ Nice work, Anna, especially the last paragraph. Classical notions of particles are rather useless when applied to off-shell gauge bosons. It's bad enough doing it with virtual photons, but they're pretty tame compared to gluons. ;) $\endgroup$– PM 2RingCommented Apr 20, 2018 at 6:35
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$\begingroup$ @Prahar: While the addition of two velocities < c certainly always is < c; this argument doesn’t hold if both the velocities to be added are equal to c. $\endgroup$– AntonCommented Apr 20, 2018 at 22:38
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1$\begingroup$ @PM 2Ring. Interestingly enough the Higgs mechanism involves a quartic scalar field theory. This has a degenerate vacuum state which permits Goldstone particles to be absorbed by the $W^{\pm}$ and $Z$ particles. A nonabelian gauge field is self interacting and results in a quartic term, though the field is vector. QCD in a strong limit is strongly self interacting and off shell gluon fields form a sort of self-energy condition. Most of the mass of a hadron is due to this mass-gap. $\endgroup$ Commented Apr 25, 2018 at 0:23