I understand the simple version answer to this question what does not make sense is if most of the matter around us is normal matter then for the blackhole to losemass from the virtual particle pairs. Doesnt more antimatter or antiparticles need to fall in then positive?
I understand the temperature or radiation one should see is one of the particles escaping the virtual pair. But unless the virtual pairs are always created with a slightly above 50% chance that the anti particle always is crossed the event horizon and the regular one on the other side how is any mass actually being lost?
Ive looked and am really surprised nobody's asking this. Conservation of energy isnt a valid answer. Because if a particle escapes why wouldn't it just vanish instead of the one in the blackhole?
My understanding is that hawking radiation has more to do with the fields in bent space time and the reference frame point then actual virtual particle pairs. Thats just the simple answer.
Also if mass is just energy and a particle and antiparticle collide they release energy How would this released energy escape the blackhole if it happened inside the event horizon. Wouldnt this just stay trapped in yhe gravity well. And if gravity separates the virtual pair and they dont annihilate then new energy has been created hasn't it?
I know im miss some things here. I just haven't found a satisfactory explanation for how the virtual pair reduces any mass inside the blackhole. Unless the two particles are quantum correlated and when one interacts with one inside the blackhole it basically teleports to the one outside the blackhole and the pair ceases to exist because it cant exist for more then a fraction of time anyways.