Standard set up and review:
Let us consider $SU(N)$ SQCD with $N_f$ flavors as our electric theory (just like in Seiberg's paper) and also let $N_f \geq N$. This theory is completely Higgsed in the IR and we end up describing the low energy degrees of freedom using mesons $M$ and baryons $B, \tilde{B}$ out of the Higgsed (massless in the UV) degrees of freedom.
The idea is that we can describe the theory using $M, B, \tilde{B}$ in the IR. I thought that this is correct also when $N_f < 3N$, i.e., when the theory becomes confining. It turns out that there is a conformal window and the theory flows to an IR fixed point when $3N/2 < N_f < 3N$.
The resulting SCFT is strongly coupled and after passing through the conformal window lowering further $N_f$ the theory should be confining. But when we calculate the scaling dimension of the meson, for example, we find that it must be a free operator, and even the whole theory to be free. Thus this is not the correct description of the theory at the confining phase after the conformal window and we need to use a dual magnetic theory theory that is indeed free in that region.
My point:
Now, I do not understand very well this very last bit. My question is the following:
Why would the dual magnetic theory correctly describe the physics of the original strongly coupled IR electric theory in the region $N_f < 3N/2$?
The duality holds only within the conformal window, i.e. the electric SCFT is dual to the magnetic SCFT only within the window. So when one SCFT is very strongly coupled I understand why we can use the dual one. But why would that be the case outside the conformal window?