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Diagram of cord winding around cylinder

A uniform solid cylinder of mass $M$ and radius $R$ is free to rotate on frictionless horizontal axle. Two masses m hang from the two cords wrapped around the cylinder. If the system is released from rest then the tension in each cord will be

I want to solve this using the work energy theorem, so I used $$2mgh=mv^2+\frac{1}{2}I\omega^2$$ but what values should I put in for $v$ and $\omega$ in order to get tension?

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    – ACuriousMind ♦
    Commented Oct 11, 2017 at 11:02

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Use $\omega =\frac v R$ to get a relationship of the form $v^2=k h$ where $k$ is a constant related to the given quantities and compare it with the constant acceleration kinematic equation $v^2=u^2+2as$ to get the acceleration $a$ of a mass $m$.
Finally apply Newton’s second law to mass $m$.

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