# How to achieve temperature below absolute zero?

Firstly i am not a physicist, so kindly go easy on me.
So i grew up believing that absolute zero is the bottom of temperature chart. Recently i read that scientist achieved the feat of going below that mark.

http://www.livescience.com/25959-atoms-colder-than-absolute-zero.html

According to what i know the molecules stop moving at absolute zero, and hence one cannot go past that temperature mark.

So my questions are:

1. are these results are real or there is some other meaning they are implying?
2. How is it possible to achieve temperature below absolute zero?
3. theoretically what is the highest temperature one can reach, if the highest speed a molecule can reach is speed of light? (considering movement of molecules determine their temperature).

PS: I have read the related links/similar questions and duplicates, but couldn't understand it really. So please be kind enough to explain in layman terms, and please edit the question if there are any misconceptions.

• This is an example of sensationalism. They are using the definition of temperature in terms of entropy not in terms of average kinetic energy (which is what we humans generally understand temperature to mean). So I suggest you ignore it. – lemon Nov 26 '16 at 11:28
• @lemon : so there is no such thing as negative temperatures ? – Bhagyesh Chaudhari Nov 26 '16 at 11:34
• @BhagyeshChaudhari It depends on how you define 'temperature', is the point. By the standard definition that you understand - the average atomic kinetic energy - the answer is no. – lemon Nov 26 '16 at 11:41
• Possible duplicates: physics.stackexchange.com/q/1775/2451, physics.stackexchange.com/q/21851/2451 and links therein. – Qmechanic Nov 26 '16 at 14:13
• I will write this as a comment instead of an answer because I'm not able to carefully research that it's accurate. I believe there is a highest possible temperature because fundamental particles colliding with each other at close enough to the speed of light will have more energy than the Planck energy and form a black hole on collision. The black hole may then evaporate in about the Planck time releasing photons. – Timothy Aug 27 '18 at 2:40

First of all: abandon the notion that temperature is proportional to (kinetic) energy. It is only valid in classical systems where the energy is mechanical. It is not a good way to define temperature.

So what is temperature? Two systems have the same temperature when they are in thermodynamic equilibrium. Otherwise heat will flow from the warmer to the cooler system until equilibrium is established. On a microscopic scale, transport of heat occurs by random processes. The condition for thermodynamic equilibrium is that the combined system is in its most probable state. It is the macroscopic state (described by macroscopic parameters like temperature and total energy) in which the number of microstates (all the different ways in which the positions and energies of atoms and electrons can be arranged that are compatible with the macrostate) is largest. Let us call this number Ω. It is a really gigantic number, normally very rapidly increasing with internal energy.

Now back to the two systems that are in thermodynamic equilibrium, let us call them A and B. It is reasonable to assume that Ω of the total system is the product of $\Omega_A$ and $\Omega_B$. When Ω of the total system is at its maximum for the distribution of energy between A and B, it won't change in first approximation when a small amount of energy is transferred from A to B. If this small transfer of energy increases $\Omega_A$ by 1 %, then $\Omega_B$ must go down by 1 %.

So the general condition for two systems having the same temperature is that they have the same fractional change of Ω with internal energy. (We do not really need to mention entropy, but it is a logarithm of Ω and the requirement that both systems have the same derivative of entropy with respect to energy is the same condition.)

Now, in systems where there is a highest possible energy (for example spins in a magnetic field), Ω cannot always increase with energy. For high energies it must start go down somewhere. The fractional change of Ω with energy is then negative. This means that temperature is negative.

To expand slightly on @lemon's comment, the way you describe "temperature", related to movement of particles, cannot be below zero.

However, entropy, which has to do with the amount of "states" a physical system might be in at a given time, can behave in non-standard ways as soon as the system is not "thermal". Usually, a gas made of particles which don't interact too much at large distances (they would not interact with all the other particles at the same time) obey standard statistical laws were temperature and entropy are clearly defined from the movement of the particles.

In some very specific systems, for instance with highly correlated particles (which would all interact with all the others at the same time), the entropy can behave very differently, and the movement of individual particles is not what matters most. Typically, even if particles all move, they cannot move independently one from the other, so the amount of available states is limited. In these conditions, temperature is defined differently, so that it appears in similar equations as standard statistical physics. But its value is not necessarily limited to zero.

To summarize, temperature, as described in your reference, may be negative because it has a different definition.