My confusion is-
1) While taking limits, tension at end B of rod is taken 0, The function comes showing maximum Tension at end A.
But it seems to me that that at end A, T must be 0 as x=0 and at end B it must be max. Why?
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3$\begingroup$ Possible duplicate: A rod of length L & mass M is rotating in a circle about one end then calculate tension in the rod at a distance x from the support $\endgroup$– hxriCommented Apr 17, 2016 at 14:20
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$\begingroup$ Read this: Find Tension of the rotating rod at a distance x and see how the tension depends upon the distance as $(L^2-x^2)$ $\endgroup$– hxriCommented Apr 17, 2016 at 14:22
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$\begingroup$ If the tension at x = 0 were zero, the rod would not fly off if you let go. $\endgroup$– Chet MillerCommented Apr 17, 2016 at 14:30
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1 Answer
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The tension force at any point in the rod provides the force that keeps the parts of the rod further from the centre of rotation moving in a circle. For points closer to the centre there is more mass to swing around i.e. a larger centripetal force is required, so the tension is larger.
I'm assuming your thinking of a rod rotating in a horizontal plane. In a vertical plane the tension will be more when B is below A and less when is above. You could even get compression in the rod if it's rotating slowly enough.
