0
$\begingroup$

I have derived the result for 2 positive charges, and for one positive one negative can be obtained by using the minus sign correctly. But I was unable to extend it or solve for n charges. Is my extension right? (I have maintained dimensions and extended it that's all) Or what is the correct derivation for it? enter image description here

Improve this question
$\endgroup$
2
  • $\begingroup$ How about you walk us through the logic you used to arrive at your answer for the 2-charge case, and we can discuss whether it generalizes to more charges. Or maybe easier: how do you check if you're right in the 2-charge case? $\endgroup$
    – Mike
    Commented Apr 2, 2016 at 13:49
  • $\begingroup$ Oh, I simply equated the magnitude of force and opposed the direction of force by the 2 charges. It does work for the 2 charges. But I don't know about multiple ones. $\endgroup$
    – Shodai
    Commented Apr 2, 2016 at 14:54

0

Reset to default

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.