3
$\begingroup$

Can we distinguish if a general wave or disturbance $f$ (not necessarily electromagnetic) which satisfies the wave equation \begin{equation} \frac{1}{v^2}\frac{\partial^2 f}{\partial t^2} = \frac{\partial^2 f}{\partial x^2} + \frac{\partial^2 f}{\partial y^2} + \frac{\partial^2 f}{\partial z^2} \equiv \nabla^2 f \end{equation} is transverse or longitudinal?

$\endgroup$
  • $\begingroup$ What do you mean by "in general"? Do you want the identification to be based entirely on the nature of the wave function? $\endgroup$ – SchrodingersCat Mar 6 '16 at 6:15
  • $\begingroup$ @SchrodingersCat Yes. Maybe I myself am not very sure at this point, but is there a way to extract information about the mode of propagation by looking at the wave equation? If not, how else could we distinguish them? $\endgroup$ – Everiana Mar 6 '16 at 7:05
  • $\begingroup$ I think that you have to consider a wave equation in dimension>1 since the notions of longitudinal and transverse usually refer to vectors. $\endgroup$ – Urgje Mar 6 '16 at 10:43
  • $\begingroup$ @Urgje yes, the full equation is actually three dimensional. If there is three dimensional, how would I distinguish it then? $\endgroup$ – Everiana Mar 6 '16 at 20:41
  • 2
    $\begingroup$ No, because the wave equation applies to both longitudinal and transverse waves. Physical context should tell you what $f$ is supposed to be. $\endgroup$ – Javier Mar 7 '16 at 1:47

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.