There is a fairly general discussion of relativistic aberration on John Baez's Physics FAQ site, and a more mathematical treatment on Wikipedia. The formula telling how the original angle is changed for the moving observer is:
$$ \cos\theta_O = \frac{\cos\theta_S - v/c}{1 - \cos\theta_S\,v/c} $$
I knocked up a quick graph in Excel to see what happens with increasing speed:
The angle zero means directly behind while the angle $\pi$ means directly ahead. The graph shows that for values of $v/c$ near unity the filed of view is concentrated ahead of the observer as you describe.
As you approach $c$ the whole field of view is concentrated into a spot directly ahead of you. However light coming from directly behind you experiences no aberration even in the limit of $v \rightarrow c$. So you would never see the whole $2\pi$ no matter how fast you travel.