14
$\begingroup$

How many "colors" do exist?

Our perception: As far as I know, colors are just different frequencies of light. According to wikipedia, we can see wavelengths from about 380 nm und 740 nm. This means we can see light with a frequency from about $4.051 \cdot 10^{14}$ Hz to about $7.889 \cdot 10^{14} $ Hz. Is this correct? I don't know if time (and frequencies) are discrete or continuous values. If both are continuous, an uncountable number of "colors" would exist. If it is discrete, there might still exist no upper bound.

An upper bound? I found the article Orders of magnitude of frequencies. The Planck angular frequency seems to be by far higher than all other frequencies. Is this the highest frequency which is possible? Do higher frequencies make sense in physics?

Why do I ask this question: I am imagining the vector space $\mathbb{R}^4$ like the $\mathbb{R}^3$, but with colors. I need an infinite amount of colors if this should make sense. In fact the number has to be uncountable.

Improve this question
$\endgroup$
3
  • 1
    $\begingroup$ You now have two quite good answers, one related to physical limitations and one related to human physiology. You do not say what your R^4 is to be used for or how, so I am waiting for your choice. $\endgroup$
    – anna v
    Commented Jan 19, 2012 at 5:01
  • $\begingroup$ @annav: "My" $\mathbb{R}^4$ has no special use case. I am a math student and if we get a "practical example" of a vector space it is most of the time $\mathbb{R}^n$. By the way, users who read this might also like andrewkeir.com/creative-collection/… $\endgroup$
    – Martin Thoma
    Commented Jan 19, 2012 at 6:15
  • 2
    $\begingroup$ I've grown up thinking that there are $(FFFFFF)_H=(16,777,216)_{10}$ colors :D. $\endgroup$
    – Manishearth
    Commented Mar 4, 2012 at 12:34

6 Answers 6

Reset to default
12
$\begingroup$

A human eye may only distinguish thousands or millions of colors – obviously, one can't give a precise figure because colors that are too close may be mistakenly identified, or the same colors may be mistakenly said to be different, and so on. The RGB colors of the generic modern PC monitors written by 24 bits, like #003322, distinguish $2^{24}\sim 17,000,000$ colors.

If we neglect the imperfections of the human eyes, there are of course continuously many colors. Each frequency $f$ in the visible spectrum gives a different color. However, this counting really underestimates the actual number of colors: colors given by a unique frequency are just "monochromatic" colors or colors of "monochromatic" light.

We may also combine different frequencies – which is something totally different than adding the frequencies or taking the average of frequencies. In this more generous counting, there are $\infty^\infty$ colors of light where both the exponent and the base are "continuous" infinities.

If we forget about the visibility by the human eye, frequencies may be any real positive numbers. Well, if you're strict, there is an "academic" lower limit on the frequency, associated with an electromagnetic wave that is as long as the visible Universe. Lower frequencies really "don't make sense". But this is just an academic issue because no one will ever detect or talk about these extremely low frequencies, anyway.

On the other hand, there is no upper limit on the frequency. This is guaranteed by the principle of relativity: a photon may always be boosted by another ditch if we switch to another reference frame. The Planck frequency is a special value that may be constructed out of universal constants and various "characteristic processes" in quantum gravity (in the rest frame of a material object such as the minimum-size black hole) may depend on this characteristic frequency. But the frequency of a single photon isn't in the rest frame and it may be arbitrarily high.

Improve this answer
$\endgroup$
7
  • 2
    $\begingroup$ I'm reading as closely as I can, but it seem that you addressed the prospect of a lower limit and an upper limit but didn't really address the finiteness of the spectrum. Does quantum not place any sort of limits on the # of allowable frequencies within a given band? It seems like, at some point, virtually everything in the universe can be hypothesized to have discrete states, I have trouble believing that photons would be different. $\endgroup$
    – Alan Rominger
    Commented Jan 18, 2012 at 21:29
  • 3
    $\begingroup$ @Zassounotsukushi: QFT restricts the energy that can be stored in a mode of oscillation at any given frequency to discrete values. But it doesn't restrict the possible frequencies. That's another conclusion you can get from the Lorentz invariance argument Lubos mentioned: a photon can be red-/blueshifted to any frequency by making an appropriate change of reference frame. (Unless Lorentz transformations themselves are quantized, but that's a rather crazy idea.) $\endgroup$
    – David Z
    Commented Jan 19, 2012 at 2:20
  • $\begingroup$ @David: The same argument that gives a lower bound on frequency gives a lower bound on two distinguishable frequencies. Two frequencies whose wavelength is different by an amount which makes less than a cycle over the observable universe are indistinguishable. Needless to say, this has nothing to do with vision. $\endgroup$
    – Ron Maimon
    Commented Jan 19, 2012 at 2:21
  • 3
    $\begingroup$ Dear @Zassounotsukushi, apologies if the explanation was not written clearly in my answer. I think that I wrote that the frequency is a genuinely continuous quantity but I may have failed to justify the statement. David Zaslavsky is totally right and Lorentz invariance is able to prove the continuity of the frequencies, too: nothing can change about it by quantum effects (except if one works in a box which only allows standing waves). BTW, David, a quantized Lorentz group could surely not be a usual subgroup of $SO(3,1)$ - no "dense enough" subgroup like this exists. $\endgroup$
    – Luboš Motl
    Commented Jan 19, 2012 at 7:16
  • 1
    $\begingroup$ Dear @Ron, I agree you may be right: the Hubble-scale issues were sketched in the part of my answer about the lower limit on frequencies. For a universe with boundaries, one could indeed get a quantization of frequencies, like in a box, but with an insanely low spacing. $\endgroup$
    – Luboš Motl
    Commented Jan 19, 2012 at 7:17
11
$\begingroup$

The colors which are perceived by people are defined by the degree to which the light will excite the red,green, and blue photoreceptors in the cone cells of the eye. There are only three discrete colors we can perceive, and they are red, green, and blue. The statistics of the relative and absolute excitations, the amount of red,green, and blue averaged over many cells and over many time steps, defines the perceptual color space. It is somewhat vague, because the longer you average, and the more cells you have to average over, the finer you can distinguish the colors. But the gradiations become pointless after a certain amount of refinement.

The wavelengths of light are not in any way primary, the response of the three photoreceptors is. The reason different wavelengths have different colors is because they excite the different receptors differently.

This means that there is a three dimensional subspace of colors, which is defined by the degree to which the brain can integrate the signal for red,green, and blue, and determine the intensity of each component. The only way to be sure of the number of gradations of each is to do psychological testing: look at a division of the intensity scale for a pure color (a color which excites only one of the photoreceptors) and see how close the intensity can be before neighboring intensities cannot be reliably distinguished. It is probably between 255 and 512 steps for red and green in the standard range of a monitor, and between 100 and 256 for blue (this is a guess based on my own memories of my own perception). This is in the standard "octave" of a computer screen (the screen is not close to blinding, nor is it ever barely visible, but the eye is logarithmic, so this range should be the same in the total number of octaves, at most 10, I'll say about 4, and more for red/green then for blue, so that the right estimate is about 1000^3, or a billion colors.

But this does not take rhodopsin response into account. The rhodopsin response is separate from the color response, because the rhodopsin range is overlapping with all three receptors. If you include rhodopsin as separate, you would have to multiply by another 1000 possible values, or a trillion colors. Some of these colors would only be accessible by artificial means--- you would have to stimulate rhodopsin without stimulating the red, green, or blue phosphors, and this might be possible chemically, like if you have taken a psychoactive drugs, dream states, oxygen deprivation. Another way might be to use afterimages, which will remove the sensitivity of certain receptors.

Improve this answer
$\endgroup$
0
9
$\begingroup$

If you are considering human vision there is a definite (and surprisingly small) number of distinguishable colors.

This is known as a MacAdam diagram and shows a region around a single color, on a chromaticity plot, that is indistinguishable from the color at the center.
The total number of colors would be the number of ellipses needed to completely fill the color space. Obviously this depends on the individual's age, sex, lighting, etc

enter image description here

Improve this answer
$\endgroup$
1
  • $\begingroup$ It should be noted that the ellipses in the image you've attached have been scaled up by a factor of 10. $\endgroup$
    – HISEROD
    Commented Jul 23, 2023 at 20:13
1
$\begingroup$

While a specific frequency of light has a color, it does not uniquely define that color. Human eyes have 3 different "color" receptors, each of which is more sensitive to some freqencies than others. See this image.

There are an infinite number of colors, but there is probably some limit as to how finely a person can distinguish between different intensities coming from each type of photoreceptor.

Improve this answer
$\endgroup$
0
$\begingroup$

First, the color is determined by the spectrum of the electromagnetic radiation in the visible range. Most colors cannot be produced by a single frequency. On the other hand, not every spectrum gives a different color, because we only have three different receptors in our eyes (actually there are four, but one type is not used for determining color). Therefore the complete color reception is based on a three-dimensional space (this is why almost all color spaces, like RGB, HSV, HSB, YUV have three parameters). Note however that despite of this, it is not true that all colors can be generated by mixing just three colors (you can describe all colors in e.g. sRGB, but then you need negative values for some colors). This is because not all activation patterns of the receptors can be produced by light. Indeed, all spectral colors (that all colors which correspond to light of just one fixed frequency) cannot be mixed from anything else. Also note that this three-dimensional space also contains the brightness (the HSV, HSB and YUV color spaces separate that out as a specific coordinate), therefore if you factor that out, the true color space has only two parameters left.

However, we cannot distinguish arbitrary close colors, therefore the true color spectrum is actually finite. However there's no way to strictly define the number of colors; indeed the translation of spectra into colors is not as well defined as the above would make you think. For example, our perception makes a white balance (that's why in analog photography the colors look wrong if you made e.g. a photo in electric light with daylight film, and why digital cameras come with automatic white balance), also of looking for a longer time at the same color at sufficient brightness, the receptors get "tired" (that's why if you then look at a white wall, you'll see the image in complementary colors). Also certain patterns of intensity change are perceived as colors. In other words, whatever you do will only be an approximation to true color perception.

Improve this answer
$\endgroup$
-2
$\begingroup$

How many colors exist?

None.

Our perception: As far as I know, colors are just different frequencies of light. According to wikipedia, we can see wavelengths from about 380 nm und 740 nm. This means we can see light with a frequency from about 4.051⋅10^14 Hz to about 7.889⋅10^14 Hz. Is this correct?

As far as I know, yes. Though I will add that some people can see into the ultra-violet a little. I imagine some can see into the infra-red a little too.

I don't know if time (and frequencies) are discrete or continuous values. If both are continuous, an uncountable number of "colors" would exist. If it is discrete, there might still exist no upper bound.

As far as I know a wavelength or frequency can take any value, and the vary smoothly.

An upper bound? I found the article Orders of magnitude of frequencies. The Planck angular frequency seems to be by far higher than all other frequencies. Is this the highest frequency which is possible? Do higher frequencies make sense in physics?

I think there could be some kind of upper bound to a photon frequency, due to a speed-of-light limitation. But I can't prove it. And it's way beyond the UV cutoff, so I don't think it's relevant.

Why do I ask this question: I am imagining the vector space R4 like the R3, but with colors. I need an infinite amount of colors if this should make sense. In fact the number has to be uncountable.

You might say that, but when you said How many colors exist? I said none. Because light exists, and this light has a wavelength, a frequency. But colour is a quale. It only exists inside our head. So in truth, it doesn't exist at all.

Improve this answer
$\endgroup$
2
  • 2
    $\begingroup$ "I think there could be some kind of upper bound to a photon frequency, due to a speed-of-light limitation. But I can't prove it." Ehh... no? How'd you derive a frequency bound from the photon speed? Please enlighten me. $\endgroup$
    – Danu
    Commented Nov 4, 2016 at 14:25
  • $\begingroup$ @Danu : light has a transverse wave nature. Think of a transverse wave in an elastic bulk. It goes this way → at a speed $v_s = \sqrt{\frac {G} {\rho} } $. As it does there's a waving going on, first this way ↑, then this way ↓. The frequency of this cannot be unlimited because the up-and-down displacement would exceed the elastic limit of the material. The expression for light is of course $c_0={1\over\sqrt{\mu_0\varepsilon_0}} $. $\endgroup$
    – John Duffield
    Commented Nov 4, 2016 at 14:42

Not the answer you're looking for? Browse other questions tagged or ask your own question.