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I just wanted to double-check these three statements, as I'm not entirely sure I understood them completely:

1) A stationary electric charge (let's say a proton) produces electric field. 2) A moving non-accelerating proton produces also magnetic field. 3) An accelerating proton produces electromagnetic waves.

Is that true? Does an accelerating proton also produce magnetic field or only electromagnetic waves? What is the rationale behind the third sentence? Is it because some of a proton's energy gets lost in the process of changing velocity and transfers into the electromagnetic wave energy?

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  • $\begingroup$ Note: I think the interesting question here is: In a fixed frame of reference, comparing zero vs. non-nonzero acceleration of an electrical charge, how does the change in time of the electrical field components in some distance of the ordiginal source differ? The answer must be found in the Maxwell equations, e.g. $\nabla \times \mathbf{B} = \mu_0\left(J + \varepsilon_0 \frac{\partial \mathbf{E}} {\partial t} \right)$. The question is why constant J gives a significantly different behaviour for the fields than a J which changes in time. Put differently: Why are field lines static for J const? $\endgroup$ – Nikolaj-K Jan 15 '15 at 10:42
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1) A stationary charge that has always been stationary is associated with an electric field and only an electric field. The electric field points towards the charge and every point that us equally far away has an equally strong field and the fields gets four times as weak if you go twice as far away.

2) A uniformly moving charge that has always been stationary is associated with a magnetic field and also an electric field. And the electric field for the moving charge is different than the electric field for the stationary charge in #1. For instance it points towards the line the charge is moving on, and always to a point where the charge used to be but no long is (in fact you can imagine that at every the particle was at a certain place that a sphere expands from that place and time at the speed of light and on that sphere the electric field points towards where that particle was even though it isn't there any more) and points that are currently equally far from the charge do not have equally strong fields.

But wait, there is more! When you see a pure electric field, a friend moving relative to you sees a combination of electric and magnetic fields. And the electric and magnetic fields you see for the moving charge at some point are literally just the electric and magnetic field you'd see when a friend moving with the charge saw a pure electric field pointing radially from/to the charge. So really your motion has just made the electric field from the proton's frame look like an electric field.

You can combine electric and magnetic fields into a single unified Faraday field with six independent components that different people break into different pieces to see electric and magnetic fields.

3) If you are accelerating at a place p at a moment t then there is again an expanding shell moving outwards from that place p expanding at the speed of light, c. And on this shell there are additional electric and magnetic fields, different than any we have seen before.

These will be in addition to those due to the location and velocity of the charge. They can point in different directions than before. And even though they are different, they share some properties for instance the new magnetic field is still orthogonal to the the new electric field. But other things are different, for instance they don't get weak as quickly you could go out a million times as far out and the new fields from the acceleration only get a million times smaller on average so really far away that's what you are likely to notice. The fields caused by the acceleration. On the other hand if the acceleration was a tiny acceleration you might have to go very far before that is the stronger field.

There is a sense where (squared) field strength is conserved and so just moved around. And the reason the acceleration fields get weaker less quickly is because the flow of field strength is orthogonal to both the electric and magnetic fields. In fact that is why you need magnetic fields to allow electric fields to change, you need magnetic fields to flow the field strength. And so the fields associated with the acceleration are trying to send the energy outwards to the future location of the shell since the new (acceleration based) fields are both tangent to the surface of the shell. Magnetic fields due to a single charge are always tangent to the expanding shell but for the acceleration fields both are tangent, so if it was just up to them all the field strength would flow outwards to the next instants slightly bigger shell.

This contrasts with the static fields which have the electric field pointing orthogonally to the shell and since the magnetic field is orthogonal to the electric field and tangent to the shell, the magnetic field do the the position of the charge is zero (it is both orthogonal to and tangent to the shell). So on its own the static fields wouldn't flow any field strength.

But they do interact since the field strength flows orthogonal to the total fields. Plus there are the fields due to velocity, which on some points of the shell help and in some places hurt. When they keep field strength from travelling outwards they could be redistributing it across the shell

And the fields due to the velocity are sometimes helping and sometimes hurting because the part in the direction of the acceleration has a part that (like the static field) doesn't contribute to flow of field strength. While the part of the velocity orthogonal to the acceleration actually just contributes to another acceleration field but one that in some parts if the shell makes the other one stronger and in other parts makes it weaker.

Finally. It is important to note that the acceleration fields flow the field strength in a way to make there be more fields on the later shells that are like themselves, so when the other fields cancel each other out the acceleration fields succeed at going to the next shell in a self propagating way.

So when the acceleration fields have their way they stay at full strength and have progeny like themselves but when the other fields have their way they don't flow the field strength out to the next part of the shell.

So in a battle like that it isn't surprising that in those later shells it is almost all acceleration fields.

So these new fields that are associated with acceleration are not just the same fields that look different because a different person is looking. They are different fields. Because they point tangent to the shell, so flow their field strength outwards to the next shell.

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For all of these points it is important that you ask 'relative to what' because the idea of an electric and a magnetic field was shown by Maxwell to be a different way of looking at the same thing. So if we were in the frame of reference of a charged particle moving past another charged particle (which would look like a charged particle moving past us in the opposite direction!) we could see a magnetic field rather than an electric one which could be the opposite of what the other particle sees So to answer your points, number 1 and 2 are true and for point 3: There are two separate questions here. 1) The idea of a field in quantum field theory is that it can be thought of as an area of effect caused by waves from a source. So whenever you think about a field you can think about things in the field being effected by EM radiation and 2) You might be talking about 'synchrotron radiation' which is, as you say, generated by forcing charged particles to accelerate...so yes to point 3 too. Cheers

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