I've noticed that when I apply the front brakes on my bike it stops quite quickly. If I apply the back brakes at the same speed, it skids rather than stopping quickly. Why?
$\begingroup$
$\endgroup$
5
asked Oct 30, 2014 at 6:05
-
6$\begingroup$ This applies to all vehicles, not just motorbikes. For the same reason the front brakes on cars are made to be the most powerful ones (generally discs even with rear drums - also bigger, vented discs and bigger callipers). $\endgroup$– HollowayCommented Oct 30, 2014 at 10:33
-
1$\begingroup$ @Trengot - A big reason for continuing to use drums on the rear is that it's far easier to implement the parking brake using drums vs disks. $\endgroup$– Hot LicksCommented Oct 30, 2014 at 15:22
-
1$\begingroup$ The rear brakes actually become less efficient the more you brake no matter which brake you are using. This is explained in the answers, but they don't mention that even when you use the rear tire to brake you are slowing the vehicle, $\endgroup$– DJSpudCommented Oct 31, 2014 at 14:37
-
$\begingroup$ @Trengot Not even to all wheeled vehicles; To all that have more than one "axle" - not to Sedgeway, for example. (Ok, yes, a fighter jet is wheeled, and it does apply after landing ;) ) $\endgroup$– Volker SiegelCommented Oct 31, 2014 at 18:17
-
1$\begingroup$ @siegel, without multiple axles, defining a rear brake is difficult. $\endgroup$– HollowayCommented Nov 1, 2014 at 22:57
Add a comment
|
5 Answers
$\begingroup$
$\endgroup$
14
Using the brakes on the front of the bike causes your weight to shift forward. Additional weight allows more force before the tire will slip (skid). If you brake hard enough the back tire of your bike will lift up and at that point all of the mass is distributed on the front tire.
Remember the maximum force is $F_{max} = \mu F_{normal}$ and $F_{normal}$ is proportional to the distribution of weight on the tire so as weight shifts forward $F_{normal}$ increases and therefor the maximum stopping force $F_{max}$ increases.
Braking with your back tire doesn't shift weight onto the back tire so its stopping power doesn't increase.
Wikipedia explains this in great detail in the Bicycle and motorcycle dynamics article.
answered Oct 30, 2014 at 6:15
-
3$\begingroup$ Doesn't using rear brakes shift weight forward? $\endgroup$– JiKCommented Oct 30, 2014 at 13:41
-
4$\begingroup$ Technically, the weight doesn't "shift forward". Rather, the force generated by deceleration adds a vector force to the purely downward force due to weight, and that added force has a vertical component which adds to the downward force on the front tire and subtracts from the downward force on the rear tire. $\endgroup$ Commented Oct 30, 2014 at 15:21
-
6$\begingroup$ @JiK: If the vehicle's center of mass is above the surface the wheels are riding on (likely true for almost anything other than a monorail), applying either brake will increase the downward force on the front wheel and reduce the force on the back wheel. If one only uses the rear brakes, braking force will be limited to the level that would reduce the rear wheel down-force to nothing. If there's no force pushing the rear wheel onto the ground, it won't be able to supply any braking force. $\endgroup$– supercatCommented Oct 30, 2014 at 15:21
-
1$\begingroup$ Whenever the bike slows down, your weight shifts forward, just like slamming on the breaks in a car causes passengers to fly forward. On a bike, the effect, if you are attached to the bike, is to rotate the bike up over the front tire. Since the rear tire is pulled up and off the ground, it won't have as much power to grip the road as the front tire. $\endgroup$– ColinCommented Oct 30, 2014 at 15:25
-
2$\begingroup$ Nobody mentions that there is a natural regulation loop involved in the braking with the back wheel. You break, it shifts forces forward, which lifts up the back, which looses grip, which can't then continue to brake as much, then braking force diminishes and weight shifts back to the center, which gives more grip and breaking power. There is a natural balance that intervenes which limits the braking power, but also makes so, that braking with the rear wheel will never make the bike spin around its front wheel. $\endgroup$– v.oddouCommented Oct 31, 2014 at 8:29
$\begingroup$
$\endgroup$
1
The braking force acts between the tyre and the road. The centre of mass is above this point so there is a rotational effect which increases the force going down through the front tyre and decreases the force going down through the rear tyre. Because the amount of braking force the tyre is able to produce is limited by the amount of force going down through the tyre the front is therefore able to produce more braking force than the rear.
In reality, of course, the suspension geometry is not rigid and the rider also moves forward in their seat so the effect is a bit more complicated than I've described here but the basic point stands. The front brakes are more effective because the force of braking acts below the centre of mass and this produces a rotational effect.
-
1$\begingroup$ All the complications only make the effect stronger. $\endgroup$ Commented Oct 31, 2014 at 17:19
$\begingroup$
$\endgroup$
Braking acts to stop the front tire. Friction acts at the contact patch under the front wheel to introduce a vector force directed towards the back of the bike. Since the force is not directed through the center of mass of the motorcycle/rider system, it introduces a moment or torque that acts to rotate the motorcycle and rider such that the back tire begins to come off the ground, or reduces the force conducted through the rear tire caused by the weight of the bike. The available braking or frictional force at the rear tire is proportional to the weight force directed through the rear tire.
So as the vehicle is braked, available braking power at the rear tire is reduced with positive feedback.
As the vehicle is braked, available braking power at the front tire is increased with positive feedback, for some given constant acceleration.
An analogy to running is that if you attempt to stop on a dime, you will fall on your face.
$\begingroup$
$\endgroup$
1
Lots of excellent answers here, but for fun, lets think about this backwards. Imagine you have the worlds first and only FRONT wheel drive motorcycle, and your rev it up and pop the clutch. What kind of launch do you think you would get with very little weight on the front tire? The reverse is true during braking when the deceleration shifts the weight of the bike to the from wheel.
-
1$\begingroup$ You mean the world's third+ FWD motorcycle? en.wikipedia.org/wiki/Megola, en.wikipedia.org/wiki/Killinger_and_Freund_Motorcycle $\endgroup$– OwenCommented Oct 31, 2014 at 16:13
$\begingroup$
$\endgroup$
Any change in speed is acceleration. Accelerating is equivalent to gravity being different. Braking slows you down, which means you are accelerating backwards, which means you feel gravity pulling you in the same direction as on a downhill slope. As on that downhill slope, more of the your bike's weight is supported by front wheel and less by the back wheel.
