Assume there is an infinitely large plane with a charge density $\sigma$. I understand how to derive, using Gauss' Law, that $E = \frac{\sigma}{2\epsilon_0}$ is the electric field at a distance $r$ from the plane.
However, intuitively, I don't understand how this could be true. Shouldn't the electric field be more powerful closer to the plane, since the electric field falls of as $\frac{1}{r^2}$? The larger I make $r$, the further it is from every point, meaning the electric field should decrease - shouldn't it?
Any help understanding this would be appreciated.