Are the cluster expansion (which we encounter in Statistical Physics), and cluster decomposition (in Quantum Field Theory) related to each other?
(I have a reason to believe they are)
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This stat-phys thing (cluster expansion) and that qft thing (cluster decomposition) are related by both referring to the notion of cluster, being "a small group or bunch of something.";
the former referring rather to cluster in the sense of a "group" of some particular (small, or large) number of members,
with particular and primary attention given to pairwise membership (thus not including clusters in the degenerate sense of having only one member),the latter referring rather to cluster in the sense of a "bunch" of members that are coincident,
thereby characterizing pairs of members of distinct bunches as not coincident (and including the notion of a bunch in the degenerate sense of having only one member).
(More might be said, 'cause that's really my kinda bag ...)
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$\begingroup$ I swear -I typed expansion instead of decomposition by accident. $\endgroup$– user37343Commented Jun 19, 2014 at 4:47
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$\begingroup$ Just corrected the question, about to elaborate on the question as soon as I get on my pc. $\endgroup$– user37343Commented Jun 19, 2014 at 4:50
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$\begingroup$ kevin Tah N: "I swear -I typed expansion instead of decomposition by accident." -- Presumably that refers to "expansion" in the phrase "some Weinberg bablings about cluster expansion" in the original question statement, which by now has been edited. I, in turn, admit I had read more of Weinberg's QTofF, vol. 1, §4.3 than of the Wikipedia page on cluster decomposition before submitting my answer. (I put the link there anyways; HTH.) "about to elaborate on the question as soon as [...]" -- You're not helping! (Me, anyways. ;) $\endgroup$ Commented Jun 19, 2014 at 5:31
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$\begingroup$ awesome, I remember the last time I read about this was told it could help with qcd eventually. Can you possibly provide some guide to how this, facilitates the understanding of quark properties. $\endgroup$– user37343Commented Jun 22, 2014 at 23:33