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I am aware of the Poisson and Bose-Einstein distributions as explicit distributions for Poissonian and super-Poissonian photon number distributions. Specifically, the photon number distribution for coherent light can be described by the Poisson distribution $$ \mathsf P(N=n)=\frac{e^{-\langle N\rangle}\langle N\rangle^n}{n!}. $$ Likewise, the photon number distribution of thermal light can be described by the Bose-Einstein (geometric) distribution $$ \mathsf P(N=n)=\frac{\langle N\rangle^n}{(1+\langle N\rangle)^{n+1}}. $$

Are there examples of sub-Poissonian light sources that have explicit photon number distributions? If so, what is an example of one of these distributions?

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  1. The most obvious one is an ideal single-photon source $$P_\text{id. s-p}(N=n) = \begin{cases} 1 & n=1 \\ 0 & \text{else.} \end{cases}$$ Its shot noise is sub-Poissonian $\langle \Delta N^2 \rangle_\text{id. s-p} = \langle \left( N - \langle N \rangle \right)^2 \rangle_\text{id. s-p} = 0 < \langle N \rangle_\text{id. s-p} = 1$.
  2. But also a non-ideal single-photon source is sub-Poissonian. For example, if it doesn't always generate a photon; may it be due to a finite excitation probability, quantum efficiency or collection efficiency. If the end-to-end probability to generate a single photon is $\eta$, the photon number distribution is $$P_\text{imp. s-p}(N = n) = \begin{cases} \eta & n = 1 \\ 1 - \eta & \text{else.} \end{cases} $$ Its variance $\langle \Delta N^2 \rangle_\text{imp. s-p} = \eta - \eta^2$ is still lower than the mean photon number $\langle N \rangle_\text{imp. s-p} = \eta$.
  3. Due to the properties of a mathematical convolution, all incoherent mixtures of a sub-Poissonian and a Poissonian distribution are sub-Poissonian. "Incoherent mixture" means to simply add up the photons, without interference. Just like you add the results of two dice. For example, you could have an ideal single photon source emitting on top of Poissonian light. The resulting photon number distribution is then given by the convolution of the individual distributions $$P_\text{tot}(N=n) = (P_\text{id. s-p} * P_\text{Poiss})(N=n).$$ The resulting photon number distribution has a mean value which is the sum of the mean values of the individual distributions $\langle N \rangle_\text{tot} = \langle N \rangle_\text{id. s-p} + \langle N \rangle_\text{Poiss}$. The variances also add up $\langle \Delta N^2 \rangle_\text{tot} = \langle \Delta N^2 \rangle_\text{id. s-p} + \langle \Delta N^2 \rangle_\text{Poiss}$. Since $\langle \Delta N^2 \rangle_\text{id. s-p} < \langle N \rangle_\text{id. s-p}$ and $\langle \Delta N^2 \rangle_\text{Poiss} = \langle N \rangle_\text{Poiss}$, we have $\langle \Delta N^2 \rangle_\text{tot} < \langle N \rangle_\text{tot}$.

The most prominent single-photon sources are spontaneous parametric down-conversion and quantum emitters, such as single molecules / color centers / quantum dots / atoms etc. (see here for a recent review on solid-state single-photon emitters).

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  • $\begingroup$ This is mathematics. Do you have a physical example? $\endgroup$
    – John Doty
    Commented Jan 7 at 18:46
  • $\begingroup$ @JohnDoty I've added a short paragraph on this. $\endgroup$
    – A. P.
    Commented Jan 7 at 18:55

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