A Kerr Black Hole (BH) is a spinning BH. There is an Event Horizon (EH) which is $$r_H^\pm =\frac{r_{S} \pm \sqrt{r_{S}^2 - 4a^2}}{2},$$ where $a = \frac{J}{Mc}$ and $r_{S}$ is the Schwarzschild radius. My question is, suppose I'm in a spacecraft, not in orbit, but stationary at a distance $r$. I want to have a comprehensive understanding of the effects of that BH on the spacecraft, and by extension on me. I would like to know, if I'm subjected to the effects of:
- Time Dilation: If this is present, the formula should be derived from the $g_{tt}$ component of the Kerr metric, which is $$\gamma = \frac{1}{\sqrt{1-\frac{r_{S}r}{r^2+a^2\cos^{2}\theta}}}.$$
- Tidal Force: What is the formula for this in a Kerr metric? Normally the equation is $$\frac{2GMd}{r^3},$$ with $d$ being in the instance of a human being, about 2 meters.
- Acceleration due to the gravitational attraction of the BH at that distance (surface gravity from arbitrary distance). Normally the formula is $$\frac{GM}{r^2}.$$ But I've read here that this should be multiplied by $\gamma$
- Escape velocity I need for my spacecraft from this distance $r$; normally the formula is $$\sqrt{\frac{2GM}{r}}.$$
Can the above four quantities be derived from the metric?
To prevent ambiguity, let me edit the question with the following:
- Kerr BH mass is: $10^8$ times that of Solar mass
- Spin parameter: $0.998$
- Distance $r$: $2.5208\cdot 10^{11}$ m