If we consider following $S-$matrix element:$$\left\langle\mathbf{p}_1 \mathbf{k}_2|T\{\phi(x_1) \phi(x_2)\}| 0\right\rangle_0 $$ where $\phi$ denote Klein-Gordon field, and apply the convention in Peskin and Schroeder's book: $$\langle\mathbf{p}| \phi(x)=e^{+i p \cdot x} \tag{4.94}$$
Now I find following basic fact in book:
(1) if $\mathbf{p}_1$ and $\mathbf{k}_2$ are two $\textbf{distinguishable}$ out particle states: $$\left\langle\mathbf{p}_1 \mathbf{k}_2|T\{\phi(x_1) \phi(x_2)\}| 0\right\rangle_0 = 2\cdot e^{+i p_1 \cdot x_1} e^{+i k_2 \cdot x_2} $$
(2) if $\mathbf{p}_1$ and $\mathbf{k}_2$ are two $\textbf{indistinguishable}$ out particle states: $$\left\langle\mathbf{p}_1 \mathbf{k}_2|T\{\phi(x_1) \phi(x_2)\}| 0\right\rangle_0 = e^{+i p_1 \cdot x_1} e^{+i k_2 \cdot x_2} $$
And the factor $2$ work as symmetry factor in Feynman diagram calculation.
But I am troubled for a long time understanding case (1) and (2) from $\textbf{Mathematica viewpoint}$, why from math part their have a factor $2$ difference here?