20
$\begingroup$

I don't understand all the details of Dirac mass, Majorana mass, and many other "deep" notions.

I have in mind a very simple thought experiment.

Because of neutrino oscillations we know neutrinos have mass. Thus their speed is less than $c$.

I imagine a beam of neutrinos created by some experiment in a lab. They are neutrinos, not antineutrinos, and have energy much larger than their rest mass. So they have left-handed helicity.

Now I imagine (this is a thought experiment, OK?) that some lab is moving, with respect to the one that created them, at a speed so very, very close to $c$ that it will overtake the beam, so fast that in the frame of this second lab, the speed of the beam appears to be directed towards the lab at a speed close to $c$ and in fact, opposite of their speed in the frame of the lab that created them.

In the frame of this new lab, the particles that are directed towards it have right-handed helicity.

Now two things can happen:

A) either they interact with the instruments in that lab with the same efficiency as in the original lab, and this means, since they have right-handed helicity, that they are now antineutrinos, as seen in this lab. So lepton number is not conserved.

B) or lepton number is conserved, they are still neutrinos, but having the right-handed helicity, which means the "wrong one" for neutrinos, they would interact much, much less than neutrinos of the correct, left-handed helicity. Then they are, in that lab, sterile neutrinos, but their rest mass is the same as for "normal neutrinos" and this sounds wrong.

So which is which? And please, don't throw me complicated notions that I cannot follow, Dirac vs Majorana mass, symmetry groups, chiral anomalies, etc.

Just tell me, A is right or B is right. Thanks.

Well, thanks to you folks, I have learned something. I really mixed up chirality and helicity, and that has been cleared up.

I upvoted all of you, but I cannot accept an answer to a question so ill-posed.

But your answers only bring more questions.

Rather than editing this question, I think it would be better to ask a new one. I have to digest all this before asking a well-posed question (I hope).

If, by the time I am ready, from your by answers or comments, I see a consensus that I should edit it rather than ask a new one, I shall oblige.

OK, so here is where my new question is.

Improve this question
$\endgroup$
7
  • 3
    $\begingroup$ You've discovered that helicity is not Lorentz invariant for massive particles, the left in left-handed is from being left chiral. Outrunning a neutrino doesn't turn it into a sterile neutrino. $\endgroup$
    – Triatticus
    Commented Jul 21, 2022 at 0:49
  • 2
    $\begingroup$ @Triatticus Chirality is not frame-independent either. A massive particle is equal parts left- and right-chiral in its rest frame $\endgroup$
    – rob ♦
    Commented Jul 21, 2022 at 1:10
  • $\begingroup$ @Triatticus So what is your answer ? $\endgroup$
    – Alfred
    Commented Jul 21, 2022 at 1:48
  • 2
    $\begingroup$ @rob, I'm talking about Lorentz invariance of which chirality IS Lorentz invariant. $\endgroup$
    – Triatticus
    Commented Jul 21, 2022 at 5:57
  • $\begingroup$ @Triatticus I've done some research. Looks like you are right. Can we continue this privately ? I don't know how to start a private discussion room, but I'll join you if you start one. $\endgroup$
    – Alfred
    Commented Jul 21, 2022 at 8:13

3 Answers 3

Reset to default
27
$\begingroup$

This is the question about neutrino masses.

If you outrun a left-handed neutrino, and the right-handed particle interacts like an antineutrino, then the neutrino is its own antiparticle.

If you outrun a left-handed neutrino, and the right-handed particle is sterile because the weak interaction doesn’t couple to right-handed matter particles and the matter neutrino doesn't couple (at tree level) to electromagnetism or the strong force, then the neutrino and the antineutrino are different.

The problem is that both of these possibilities are consistent with all of the neutrino data that we have so far. Nobody knows the answer to your question.

Since there are now several comments and answers pointing out that chirality, unlike helicity, is invariant under boosts, I should clarify. A particle with Dirac-type mass cannot have definite chirality in its rest frame, and therefore cannot have constant chirality in any other frame. I was implicitly assuming that "outrunning" the neutrino took some finite amount of time from its creation in a left-chiral state, and that the neutrino in its rest frame had evolved into an incoherent mixture of left- and right-chiral components.

You can absolutely change whether (or better, how much) a particle with Dirac mass participates in the weak interaction by flipping its helicity; I spent fifteen years doing this with polarized beams of electrons and neutrons.

Improve this answer
$\endgroup$
7
  • 1
    $\begingroup$ I’m not very familiar with the BEST results. But disappearance experiments are really hard, and the history of the literature is that the effects hover just out of reach. The “outrunning” thought experiment is related to oscillations in a nontrivial way. $\endgroup$
    – rob ♦
    Commented Jul 21, 2022 at 3:19
  • 3
    $\begingroup$ I don't think this is correct: The "handedness" of the neutrinos refers to their chirality, not to their helicity. Left-chiral particles do not turn into right-chiral particles when you "outrun" them, chirality and helicity only coincide when the particle is massless. You are right that no one knows whether neutrinos are Majorana or not, but this is entirely irrelevant for this question. $\endgroup$
    – ACuriousMind ♦
    Commented Jul 21, 2022 at 14:22
  • 1
    $\begingroup$ @ACuriousMind That's possible, but it would surprise me. My recollection was that the Dirac mass term $m\overline\psi\psi$ means that chirality is not preserved in the particle's rest frame, and that the correlation between helicity and chirality reappears if you boost towards the massless limit. In parity-violating electron scattering, we start with regular bulk-matter electrons, then modulate their participation in the weak interaction by flipping their spins. $\endgroup$
    – rob ♦
    Commented Jul 21, 2022 at 15:33
  • 1
    $\begingroup$ @rob Dirac masses indeed makes the mass eigenstates a chiral mixture, but that doesn't mean that chirality becomes non-conserved - it just means the mass eigenstates are not pure chiral eigenstates. Additionally, we don't even know that the neutrino mass has to be a Dirac mass (only that it cannot be a Majorana mass if our theory is a truly fundamental and not effective theory). $\endgroup$
    – ACuriousMind ♦
    Commented Jul 21, 2022 at 16:03
  • 2
    $\begingroup$ Yes, the chiral/mass basis mismatch for Dirac masses is exactly analogous to the flavor/mass basis mismatch. But that doesn't imply that chirality can change when you outrun a neutrino, it just implies that a neutrino generated as purely left-chiral won't stay purely left-chiral as it propagates. The correlation between helicity and chirality is that the faster a Dirac fermion is (i.e. the better the approximation $p \gg m$ holds), the more a state of definite helicity resembles a state of definite chirality, see Cosmas Zachos answer here. $\endgroup$
    – ACuriousMind ♦
    Commented Jul 21, 2022 at 16:53
7
$\begingroup$

Handedness is not about helicity - which, as the question points out, is something that can change depending on the reference frame - but about chirality (see also this answer of mine). The two notions are only the same for massless particles - for which then helicity is also frame-invariant since massless particle have no rest frame.

So when you try to outrun a neutrino, nothing interesting happens. Its helicity flips, sure, but its chirality - the thing the weak interaction cares about - doesn't.

If you know a bit more about massive particles and their chirality, you might now worry whether or not the propagating neutrino then is really purely left-handed - usually massive fermions propagate as a mixture of chiralities. However, this is only true for fermions with a "Dirac mass", while those with a "Majorana mass" don't show this behaviour - see this question and its answers for a discussion of whether the neutrino can have a Majorana mass. And since we can't see the right-handed part anyway if it is truly sterile, it's hard to get any experimental clarification on this except if we actually do find a right-handed neutrino somewhere.

Improve this answer
$\endgroup$
1
  • $\begingroup$ You mention Dirac mass in the third paragraph, but I don't think you make it clear enough that the second paragraph is only correct if the mass is Majorana-like. If it's Dirac then the helicity is what matters. $\endgroup$
    – benrg
    Commented Mar 1, 2023 at 1:00
5
$\begingroup$

You're confusing helicity with chirality. Chirality is Lorentz invariant, i.e. it cannot be changed by overtaking. When people talk about left-handed neutrinos, they mean that they are left-chiral. Right-chiral neutrinos do not exist (or as hypothesized sterile neutrinos, so called because they do not interact weakly). It hence is chirality that dictates behaviour in interactions.

There is nothing wrong with neutrinos having right helicity.

Improve this answer
$\endgroup$
2
  • $\begingroup$ "When people talk about left-handed neutrinos, they mean that they are left-chiral." - I don't think so. In that case they'd call the charged antineutrinos left-handed also, since they're particles of the same field, but they call them right-handed in my experience. $\endgroup$
    – benrg
    Commented Mar 1, 2023 at 0:53
  • $\begingroup$ @benrg: Antiparticles have of course the opposite chirality, so antineutinos are right-handed, and the sterile antineutrino would be left-handed. $\endgroup$
    – Peter Rottengatter
    Commented Jan 11 at 11:34

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.