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I am kind of confused by the vast number of formulas for computing the Gaussian Curvature. Having a metric tensor / an expression for the line element in 4D (e.g. $t,x,y,z$ or in spherical coordinates $t,r,\theta,\phi$), what is the most general and neat way to calculate the Gaussian Curvature of a metric?

P.S. in order to achieve maximum generality I would consider a metric tensor with off-diagonal terms, so that mixed terms will pop up in the line element expression.

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    $\begingroup$ What is your definition of Gaussian curvature in more than two dimensions? $\endgroup$
    – Javier
    Commented Mar 17, 2022 at 18:07
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    $\begingroup$ @gangio, Gaussian curvature is an intrinsic property of two-dimensional surfaces only. Do you mean perhaps Riemannian curvature tensor? $\endgroup$
    – JanG
    Commented Mar 18, 2022 at 9:01

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I think you might be talking about the sectional curvature which generalizes the concept of Gaussian curvature to higher dimensions. The sectional curvature $K$ of a 2-dimensional hypersurface is defined as $$K(\mathbf{u},\mathbf{v})={\langle R(\mathbf{u},\mathbf{v})\mathbf{v},\mathbf{u}\rangle\over \langle \mathbf{u},\mathbf{u}\rangle\langle \mathbf{v},\mathbf{v}\rangle-\langle \mathbf{u},\mathbf{v}\rangle^2}$$ where $\mathbf{u}$ and $\mathbf{v}$ are linearly independent vectors tangent to the hypersurface and $R$ is the Riemann curvature tensor. In addition, for a pseudo-Riemannian manifold such as in general relativity, the hypersurface must not be a null hypersurface. The sectional curvature reduces to the standard Gaussian curvature in 3 dimensions. The sectional curvatures in each coordinate direction are related to the the Ricci tensor $R_{ij}$ by the formula: $$R_{ij} v^i v^j = \sum_{\mathbf{e}_i\neq\mathbf{v}} K(\mathbf{e}_i,\mathbf{v})$$ where $\mathbf{v}$ is an arbitrary unit vector at a point and $\mathbf{e}_i$ is a set of $n-1$ ($n$ is the dimension) orthonormal basis vectors that are also orthonormal to $\mathbf{v}$.

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  • $\begingroup$ Thank you. Does the Gauss-Bonnet theorem hold in higher dimensions for sectional curvature? $\endgroup$
    – gangio
    Commented Mar 21, 2022 at 14:52
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    $\begingroup$ @gangio As far as I am aware, there is a generalized Gauss-Bonnet theorem that holds for Riemannian manifolds of even dimension, and it does use the concept of sectional curvature. $\endgroup$ Commented Mar 22, 2022 at 15:13

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