I've usually seen entanglement discussed when dealing with discrete basis sets. For example, if we consider the Hilbert space $\mathcal{H}_0\otimes\mathcal{H}_1$, where both $\mathcal{H}_j$ are two dimensional, the state $$ |\psi\rangle = \frac{1}{\sqrt{2}} (|\uparrow\rangle\otimes|\downarrow\rangle - |\downarrow\rangle\otimes|\uparrow\rangle)$$ is entangled, since it can't be written as $|\alpha\rangle\otimes|\beta\rangle$, with $|\alpha\rangle \in \mathcal{H}_0$ and $|\beta\rangle \in \mathcal{H}_1$.
I think that a similar thing can happen in position basis; it may not be possible to express the associated wave function $\psi(x,y)$ as $f(x)g(y)$. I believe an example of this to be $$\psi(x,y) = A(x + y) \mathrm{e}^{-x^2 - y^2}$$ where $A$ is a normalization constant. In Dirac notation I would probably write something like: $$|\psi\rangle = \int \mathrm{d}x\mathrm{d}y |x y\rangle A(x + y) \mathrm{e}^{-x^2 - y^2}$$
where $|xy\rangle = |\mathbf{r}\rangle = |x\rangle\otimes|y\rangle$. My question is: Is it meaningful to call such a state "entangled" in the same way? Is "entanglement" between coordinates different than entanglement when the underlying Hilbert spaces are discrete?