1
$\begingroup$

I'm doing some simulations of a 1D system with diffusion. One boundary has a no-flux boundary condition, while the other boundary has a prescribed-flux boundary condition with a specified mass transfer coefficient. I'm writing some tests to make sure my simulation code works as expected, and I have a number of natural test cases for the diffusion part, but I can't think of any good ones for the mass transfer part.

My thinking so far is that the mass transfer coefficient, $k_w$, has units of speed, so dividing the width of the system, $L$, by the mass transfer coefficient ought to give me a time scale that I can use for something. If the mass-transfer Biot number ($Bi = k_w L / D$, where $D$ is the diffusivity) is much smaller than one, then the diffusion is fast enough to keep the concentration approximately constant within my domain, so in that case, I would expect the remaining concentration to decay exponentially with the time scale given by $\tau = L/k_w$. Does that make sense?

Are there any other simple cases where I can know the results from simple, analytical considerations, that I can use to test my simulation code?

Update:

Just thought I could add some plots from my simulations to help explain the case I'm describing. This first plot shows the situation when $Bi \ll 1$ (or actually 0.14 in this case), in which case concentration remains almost constant inside the domain, and the exponential decay I describe works well.

plot of simulation results

In the next plot, I show the same results, but this time the diffusion is slower, and the mass transfer is higher, such that $Bi \gg 1$ (or actually 14 in this case). Here, we see the concentration near the surface is depleted, and the decay is not well described by the same exponential decay (as expected).

enter image description here

$\endgroup$

1 Answer 1

0
$\begingroup$

I like to look at edge cases which generally lead to an analytical result or intuitive trends which can be easily compared.

For example;

  1. $k_w\rightarrow 0$: you have two zero-flux boundary condities, i.e. constant concentration profiles.
  2. $k_w\rightarrow \infty$: your fixed-flux BC becomes a fixed-concentration BC at the interface which gives a linear profile in concentration.
$\endgroup$
1
  • $\begingroup$ I agree about setting $k_w=0$, that gives two no-flux boundaries, and if the concentration is initially constant, it will remain constant forever. That's a good test. But if I set $k_w$ to some large number, then the concentration will go to zero everywhere, but exactly how fast depends on the diffusion (in this case, I will have $Bi \gg 1$). So I'm not sure how I can use that as a test, other than observing that the concentration eventually becomes zero. $\endgroup$
    – Tor
    Commented Dec 10, 2020 at 12:48

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.