The heart of my question is below in bold. The rest is clarifying information or additional points of discussion - in case my assumptions are the heart of my misunderstanding.
In a two body attractive quantum mechanical system (namely the simplified Hydrogen atom - ignoring spin etc.), it can be shown that this reduces into two Hamiltonians. We find one Hamiltonian for the center of mass, and one for the behavior of the individual particles.
Assuming the individual particles are bound by their mutually attractive potential, the Hamiltonian has discrete Energy Eigenstates. The center of mass Hamiltonian, $H_{com}$, is a free particle solution. Does position-momentum uncertainty principle still apply to the wavefunction describing solutions to $H_{com}$ ?
In my undergrad QM class, the professor said that when we're in the center of mass reference frame, we ignore $H_{com}$. When I pressed him further on this, he said it wouldn't make sense for the atom's wavefunction to "spread out" in the center of mass frame (due to a $k$-space distribution of $\psi$). This didn't sit well with me, because being in the center of mass frame of the atom implies we know the center of mass momentum exactly (or to extreme accuracy), and therefore can't know the exact position (or only have an extremely inaccurate knowledge).