2
$\begingroup$

I'm working out a problem where at some point get the following product of metric tensors and momenta: $$g^{\mu\beta}g^\nu_{\space\space\alpha}(2k+\frac{q}{2})^\alpha(\frac{q}{2}-k)_\beta$$ How can I work out the metric tensor's indexes. What is the difference between a metric tensor with both indexes either up or down $g^{\alpha\beta}$ and another with one index up and the other down $g^\alpha_{\space\space\beta}$?

$\endgroup$

1 Answer 1

4
$\begingroup$
  1. The components $g^{\alpha\beta}:=(g^{-1})^{\alpha\beta}$ are the components of the inverse metric tensor, which is a symmetric (2,0) contravariant tensor.

  2. Since one lowers (raises) indices with the metric (inverse metric), respectively, the mixed tensor components $g^{\alpha}{}_{\beta}=\delta^{\alpha}_{\beta}$ are nothing but the Kronecker delta.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.