QED can calculate The probability of partial reflection but does not offer an explanation as to how this happens. Feynman created an algorithm that matched the data. I have searched but cannot find any new studies or or theories offering anything. Can anyone direct me toward any new information? Does anyone have a hypothesis of their own?
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$\begingroup$ Possible duplicates: physics.stackexchange.com/q/2041/2451 , physics.stackexchange.com/q/10301/2451 , physics.stackexchange.com/q/83105/2451 , physics.stackexchange.com/q/248726/2451 and links therein. $\endgroup$– Qmechanic ♦Commented Nov 23, 2016 at 19:55
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$\begingroup$ I will look at these more thoroughly in later. The first couple I looked at only address reflection. What I'm interested in is the 0 to 16% of partial reflection. $\endgroup$– Bill AlseptCommented Nov 23, 2016 at 20:22
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$\begingroup$ None of these links or previous questions address The 0 to 16% partial reflection. Why the distance between two surfaces of glass can make this difference. Is there a physical explanation or any theories at all. QED is simply an algorithm that fits the data and is not an explanation. Even Feynman said that. $\endgroup$– Bill AlseptCommented Nov 23, 2016 at 20:38
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$\begingroup$ This distinction that people like to make between understanding and having a correct procedure for predictions is one purely of opinion. I mean, seriously, Feynman is among the premier examples of an intuitive physicist of the twentieth century; I assure you that his procedure that you blithely dismiss as an algorithm was something he developed by understanding the mechanisms of interference and superposition in non-trivial cases. His pop-sci QED book is about understanding the theory in that way. $\endgroup$– dmckee --- ex-moderator kittenCommented Nov 23, 2016 at 22:20
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$\begingroup$ I have read it and understand it. This distinction is not my opinion, Feynman himself said he couldn't come up with a reason why it works just that it matches experiment. I'm not sure what you're saying. Are you saying there is A description of what is happening? That's what I'm looking for. Not spinning stop watches, I know what they represent. $\endgroup$– Bill AlseptCommented Nov 23, 2016 at 22:37
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