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I came across a problem that is related to the expectation value of spin-1/2. Assuming I want to find a single (or possibly a set of) spin state(s) $$\lvert\psi\rangle$$ that gives me an expectation value of say,

$$ \langle\psi\rvert Sx\lvert\psi\rangle = \pm\hbar/4 $$ $$ \langle\psi\rvert Sy\lvert\psi\rangle = \pm\hbar/4 $$ $$ \langle\psi\rvert Sz\lvert\psi\rangle = \pm\hbar/4 $$

How should I approach this problem. Is it still a simple superposition of eigenspinors or does it require spin coupling?

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  • $\begingroup$ You should be able to solve it with a superposition of eigenspinors. $\endgroup$
    – levitopher
    Commented Mar 15, 2016 at 17:06

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Representing the spin state as a spinor $$\begin{pmatrix}a\\b\end{pmatrix}.$$ $a$ and $b$ are in general complex numbers and obey the normalization condition $$|a|^2 + |b|^2=1,$$ so that leaves three independent parameters to define your spin state.

Writing the spin operators in their matrix form each of your above written equations becomes an equation for $a$ and $b$. Hence you have three equations with three unknowns and can solve for the spin state.

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  • $\begingroup$ This is what I thought. Thank you. I will do some calculus and come back here. $\endgroup$
    – Fourier
    Commented Mar 16, 2016 at 10:14

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