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The supernova 1987A explosion in the Large Magellanic Cloud 170 000 light years from Earth produced a burst of anti-neutrinos $\overline{v}_e$ which were observed in terrestrial detectors. If the anti-neutrinos are massive, their velocity would depend on their mass as well as their energy. What is the proper time inter- val between the emission, assumed to be instantaneous, and the arrival on Earth? Show that in the limit of vanishing mass the proper time interval is zero. What information can be derived about the anti-neutrino mass from the observation that the energies of the anti-neutrinos ranged from $7$ to $11$ MeV, and the arrival times showed a dispersion of $7$ s?

I'm having some troubles with the first part of this problem. When it says proper time interval I'm assuming that just means to integrate $dt'=dt\sqrt{1-(v/c)^2}$? But I need to find the velocity that the neutrinos are traveling at. I know that I can find the mass of the neutrinos using $E=mc^2$ but could I also use the fact that $m=(\hbar v)/c^2$ where $\hbar$ is the Planck constant and substitute that into $E=mc^2$ to get the velocity as $v=E/\hbar$? Then using that in the equation for $dt'$ just integrate with the limits of $t_{emission}$ and $t_{arrival}$? Also, would I use the fact that the light from the supernova arrived at earth in $1987$ and that it is $170000$ ly away as the $t_{emission}$ and $t_{arrival}$ times?

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  • $\begingroup$ Hi! Welcome to Physics Stack Exchange! Please note that this is a mathjax-enabled site. Do use that; for now it is quite vague what you wanted. For quick reference on $\LaTeX\,,$ check this quick reference. $\endgroup$
    – user36790
    Commented Feb 3, 2016 at 6:30

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You have$\frac E{m_0}$, the energy divided by the rest mass is $\gamma=\sqrt{1-\frac{v^2}{c^2}}$. The proper time is lab time divided by $\gamma$. Since you have a fixed $E$, as $m_0 \to 0, \gamma \to \infty$ and the proper time goes to $0$. For the last part, you are supposed to assume that an $11$ MeV neutrino arrived $7$ seconds before a $7$ MeV neutrino. This is in the lab frame and you can use the $7$ second time difference out of $170,000$ years to assess the lab velocity difference. It will give you a measure of the rest mass because if the neutrinos were massless they would all arrive together after traveling at $c$. If they were rather heavy, the time difference would be larger.

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