I know this has been asked before, but I am confused having read it in the context of isospin, where the creation operators act on the "vacuum" state (representing no particles) $$a^\dagger_m|0\rangle =|m\rangle$$ to create nucleon labelled by $m$ (m can be proton/neutron). And the action of annihilation operator is $$a|0\rangle =0$$ As $|0\rangle$ was already the vacuum state with no particles, what exactly did the annihilator annihilate?
In the linked question, I could understand David's and Ted's answer in the context of the Harmonic oscillator, angular momentum and such. But in this case, it is hard to imagine $|0\rangle$ as a normalized non-zero vector , which does not contain anything whose energy is not zero.