4
$\begingroup$

When studying supersymmetry breaking, people often use a spurion chiral superfield to study the soft SUSY breaking terms which enter the Lagrangian ($X=\theta^2 F$). Since we let the spurion couple to every field and assume that the messengers are at the Planck scale this is used to parametrize gravity mediated SUSY breaking. For example we can get scalar masses through, \begin{equation} \int d^4\theta \frac{X^\dagger X}{M^2} Q^\dagger Q \end{equation}

Recently I've seen papers using anomaly mediated SUSY breaking in their theories instead (one such paper can be found here). Is there a way to parametrize the SUSY breaking terms in the anomaly medaited scheme analogously to the typical gravity mediated scenario?

$\endgroup$

1 Answer 1

1
$\begingroup$

Yes, there is a way. In case you have a term in the Lagrangian that schematically looks like $$\int d^4\theta\frac{\Sigma^\dagger\Sigma}{M^2}Q^\dagger Q,$$

and the field $\Sigma$ assumes a vacuum expectation value given by

$$\langle\Sigma\rangle=M+F\theta^2,$$ gauginos for example will acquire a mass proportional to $F/M$ through a one-loop anomaly. You can read about this in detail in chapter 16 of Terning's "Modern Supersymmetry - Dynamics and Duality".

$\endgroup$
2
  • $\begingroup$ Thanks for your response. But unless I'm mistaken this spurion doesn't just couple to any possible terms as with regular gravity mediation. Is there a particle "rule" to follow for anomaly mediation? Unfortunately my knowledge of supergravity, let alone gravity, is very weak so its difficult for me to understand Terning, chapter 16 at this point and I'm working on a project involving anomaly mediation. $\endgroup$
    – JeffDror
    Commented Jun 14, 2014 at 3:00
  • $\begingroup$ I fear that I cannot give you a good answer right now, especially since I do not have the book with me. I will try to do that as soon as I can. $\endgroup$ Commented Jun 14, 2014 at 17:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.