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Jan 6, 2021 at 14:29 comment added StarBucK @JohnRennie I asked a follow up question based on your answer here physics.stackexchange.com/questions/605738/… It would be great if you can have a look :)
Mar 2, 2018 at 9:40 comment added user184271 @JohnRennie Also do we have to neglect reverse saturation current here?
Mar 2, 2018 at 8:51 comment added user184271 Solved a major doubt for me
Mar 27, 2014 at 8:16 comment added Guill Ayush, think of the gray section (depletion region) as a capacitor, the right side is left with a positive charge (electrons removed) and the left side is left with a negative charge (holes removed), so it acts like an internal battery with its positive end connected to the positive end of the external battery and likewise the negative side, therefore the "internal battery" is opposing the external battery!
Jan 26, 2014 at 18:13 vote accept Ayush Pateria
Jan 23, 2014 at 11:44 comment added Ayush Pateria I know. Electric field will be directed from N to P in the diode and from positive terminal to negative terminal in the circuit, so they are in the same direction!
Jan 23, 2014 at 11:39 comment added John Rennie No, you get a negative charge to the left of the PN boundary and a positive charge to the right.
Jan 23, 2014 at 11:23 comment added Ayush Pateria Exactly, but how is it opposite to the potential of battery? It's in the same direction right?
Jan 23, 2014 at 11:09 comment added John Rennie Because when you pull holes away to the left you leave behind a net negative charge, and likewise when you pull electrons to the right you leave behind a net positive change.
Jan 23, 2014 at 10:53 comment added Ayush Pateria How can the potential difference across the depletion layer be opposite to the battery potential? The potential in the depletion layer is from N to P and due to battery is from positive to negative terminal, so they both are in same direction, right?
Jan 23, 2014 at 10:49 vote accept Ayush Pateria
Jan 23, 2014 at 10:49
Jan 23, 2014 at 9:37 history answered John Rennie CC BY-SA 3.0