I know that
$$\tag{1}\hat{p}~=~-i\hbar \frac{\partial}{\partial x}~.$$
How can I get
$$\tag{2}\hat{x}~=~i\hbar \frac{\partial}{\partial p}~?$$
I think this simple and I'm just over thinking it, but knowing the momentum operator (1), how can I get the position operator (2)? I know $$\hat{p}=-ih \frac{\partial}{\partial x}$$ How can i get $$\hat{x}=ih \frac{\partial}{\partial p}$$