I know that

$$\tag{1}\hat{p}~=~-i\hbar \frac{\partial}{\partial x}~.$$

How can I get

$$\tag{2}\hat{x}~=~i\hbar \frac{\partial}{\partial p}~?$$

I think this simple and I'm just over thinking it, but knowing the momentum operator (1), how can I get the position operator (2)?