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Dec 21, 2022 at 6:23 history closed joseph h
Jon Custer
David Bailey
Duplicate of What is the relation between photoelectric current and frequency of incident light?
Dec 21, 2022 at 1:35 comment added Gagan Yadav Okk sir, that analogy did explained the concept really well. Thanks alot ☺️
Dec 20, 2022 at 23:33 comment added John Doty If 1000 people per day embark on ships from Europe to America, 1000 people per day arrive in America. If 1000 people per day embark on planes, they get there faster, but still, 1000 people per day arrive.
Dec 20, 2022 at 23:30 comment added John Doty The charge per unit time received is the same as the charge per unit time emitted. It doesn't matter how much time it takes for the electrons to travel: if they are slower, there are merely more in transit on average.
Dec 20, 2022 at 23:25 answer added Philip Wood timeline score: 0
Dec 20, 2022 at 23:21 comment added Gagan Yadav The confusion is that all the electrons wouldn't strike the detector plate together, there must be some gap between first photoelectron and last photoelectron that left the metalic plate, so hence, if they were moving at a higher velocity, this gap will get covered more quickly and charge per unit time should increase. Although the effect would we small, but still my textbook and teachers said it is independent of frequency. Can this be because the effect is almost negligibly small??
Dec 20, 2022 at 23:07 review Close votes
Dec 21, 2022 at 6:23
Dec 20, 2022 at 22:49 comment added joseph h As you noted, there's several questions on this site that address this. If you want an answer to your specific question, you should be more precise as to what you don't understand. "Still confused" is too vague.
Dec 20, 2022 at 22:43 answer added John Doty timeline score: 1
Dec 20, 2022 at 22:26 history edited Gagan Yadav CC BY-SA 4.0
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S Dec 20, 2022 at 22:25 review First questions
Dec 20, 2022 at 22:36
S Dec 20, 2022 at 22:25 history asked Gagan Yadav CC BY-SA 4.0