Timeline for Physical difference between $\vert S=0, m = 0 \rangle$ and $\vert S=1, m = 0 \rangle$? [closed]
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
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| Sep 28, 2022 at 3:20 | vote | accept | Lost_Soul | ||
| Sep 25, 2022 at 2:18 | comment | added | Jagerber48 | See my question and answer here. It is essentially the same question: physics.stackexchange.com/questions/402981/… | |
| Sep 24, 2022 at 20:08 | comment | added | ZeroTheHero | Reach from where? $S=0$ (singlet states) are produced in decays, the most famous application being for studying Bell’s theorem. $S=1$ can be produced by filtering after deflection in a magnetic field. | |
| Sep 24, 2022 at 19:01 | history | closed |
ZeroTheHero Meng Cheng hft |
Needs details or clarity | |
| Sep 24, 2022 at 18:50 | answer | added | hft | timeline score: 1 | |
| Sep 24, 2022 at 18:32 | review | Close votes | |||
| Sep 24, 2022 at 19:01 | |||||
| Sep 24, 2022 at 18:22 | comment | added | Lost_Soul | @ZeroTheHero Perhaps I should have phrased it as. "Any physical way to reach the representation of the states M=0S=0 and M=0S=1?" | |
| Sep 24, 2022 at 18:20 | comment | added | ShoutOutAndCalculate | @ZeroTheHero I think the OP was looking for (en.wikipedia.org/wiki/Quantum_mechanics) the graphs of the hydrogen's electron's wave function's amplitude of $s=0$ and $s=1$. | |
| Sep 24, 2022 at 18:06 | comment | added | ZeroTheHero | ^ this is a very confused comment. Since they have different $S$ any property that is S-dependent will be different. For instance, they would split differently in a Stern-Gerlach apparatus. | |
| Sep 24, 2022 at 17:51 | history | edited | Qmechanic♦ |
edited tags
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| Sep 24, 2022 at 17:37 | comment | added | Lost_Soul | @MengCheng I started along those lines. For S = 1, The constitute's "net" spin was along the same direction. Thus adding up. But this direction was orthogonal to the spin direction, thus m=0. For S=0, The net spin was opposite to each other making S=0. But could reach the states and the corresponding signs using this line of reasoning. | |
| Sep 24, 2022 at 17:35 | comment | added | Meng Cheng | They have different $S$, which is a physically observable quantity. What else are you looking for? | |
| Sep 24, 2022 at 17:31 | history | asked | Lost_Soul | CC BY-SA 4.0 |