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Qmechanic ♦
Qmechanic ♦
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A stone is attached to a string and is revolved in a circular path with constant angular velocity $\Omega$. In this state its angular momentum is $L$. If the length of the string is reduced to half and again it is revolved with the same angular velocity $\Omega$ then find angular momentum?

A stone is attached to a string and is revolved in a circular path with constant angular velocity Omega In this state its angular momentum is L If the length of the string is reduced to half and again it is revolved with the same angular velocity Omega then find angular momentum? WhyWhy we cannot use Conservation of angular momentum here Bcoz no external torque acts on it.

A stone is attached to a string and is revolved in a circular path with constant angular velocity Omega In this state its angular momentum is L If the length of the string is reduced to half and again it is revolved with the same angular velocity Omega then find angular momentum? Why we cannot use Conservation of angular momentum here Bcoz no external torque acts on it.

A stone is attached to a string and is revolved in a circular path with constant angular velocity $\Omega$. In this state its angular momentum is $L$. If the length of the string is reduced to half and again it is revolved with the same angular velocity $\Omega$ then find angular momentum?

Why we cannot use Conservation of angular momentum here Bcoz no external torque acts on it.

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Anurag
Anurag
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Angular Momentum Conservation..04

A stone is attached to a string and is revolved in a circular path with constant angular velocity Omega In this state its angular momentum is L If the length of the string is reduced to half and again it is revolved with the same angular velocity Omega then find angular momentum? Why we cannot use Conservation of angular momentum here Bcoz no external torque acts on it.