Timeline for Why are areas of graph taken with respect to $t$-axis in velocity time graphs?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Dec 21, 2021 at 14:04 | vote | accept | aaksaksyk | ||
| Dec 20, 2021 at 10:04 | comment | added | Agnius Vasiliauskas | Area represents integral of function $l = \int v dt$. Integral must be bound by $x$ axis, which is not the case with your proposed trapezoid,- it's unbounded. Your chosen reference line BC has no meaning. Because integral curve sides must be bounded by $y$ function nature and curve bottom - by $x$ axis. BC is not abscissa, thus, your trapezoid has no meaning of integral. | |
| Dec 20, 2021 at 9:21 | answer | added | Farcher | timeline score: 0 | |
| Dec 20, 2021 at 1:55 | answer | added | AJ Biffl | timeline score: 0 | |
| Dec 20, 2021 at 1:01 | history | edited | John Hunter | CC BY-SA 4.0 |
edited title
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| Dec 20, 2021 at 1:00 | answer | added | John Hunter | timeline score: 1 | |
| Dec 19, 2021 at 22:58 | answer | added | John Darby | timeline score: 2 | |
| Dec 19, 2021 at 22:13 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 4 characters in body; edited tags; edited title
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| Dec 19, 2021 at 22:12 | comment | added | aaksaksyk | The one with height -15 and length of the shorter parallel side is 1 and the longer parallel side is the blue dotted line | |
| Dec 19, 2021 at 22:08 | comment | added | JohnHoltz | What trapezium (traoezoid?) are you referring to? | |
| Dec 19, 2021 at 22:02 | history | asked | aaksaksyk | CC BY-SA 4.0 |