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Timeline for Electric field inside a wire

Current License: CC BY-SA 4.0

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Nov 29, 2021 at 10:27 history edited Vincent Thacker CC BY-SA 4.0
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Nov 25, 2021 at 10:52 vote accept Spencer
Nov 25, 2021 at 10:42 answer added user7896 timeline score: 1
Nov 25, 2021 at 10:27 comment added my2cts @VishalAnand If the current is constant and $\sigma=R/L$, the resistance per length of the resistor is constant, E remains the same. The the voltage drop is proportional to the length.
Nov 25, 2021 at 10:23 comment added Spencer @my2cts Means (potential drop across any resistor) divided by (length of that resistor) is always constant and is equal to the original electric field produced by the voltage source ??
Nov 25, 2021 at 10:16 comment added my2cts The confusion is that you use the symbol V to mean the battery voltage at the same time as the voltage drop over any length of wire or element of the circuit. Also when you say 'wire' you really mean resistor. $E=\sigma J$ so unless you change the current or the conductivity it remains constant, independent of the length considered.
Nov 25, 2021 at 9:59 comment added Dario Barišić As Roger said, if your battery outputs 5V for example, that doesn't mean that between any two points on a wire $\Delta V = 5V$, but it's actually $\Delta V = 5V * l/L$ where l is the length of the segment between two selected points, and L is the total length of the wire (assuming uniform resistivity of the wire). EDIT : Hence it follows that your electric field is 5V/L, i.e. constant throughout the wire.
Nov 25, 2021 at 9:47 comment added Spencer @RogerVadim Check the image please.
Nov 25, 2021 at 9:45 review Close votes
Nov 29, 2021 at 10:27
Nov 25, 2021 at 9:44 history edited Spencer CC BY-SA 4.0
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Nov 25, 2021 at 9:27 comment added Roger V. $\Delta V$ is between the battery terminals rather than between two arbitrary points of the wire.
Nov 25, 2021 at 9:26 history edited Roger V. CC BY-SA 4.0
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Nov 25, 2021 at 9:23 history asked Spencer CC BY-SA 4.0