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Apr 25, 2021 at 18:03 comment added anna v It is not averages that lead to the classical fields from quantum fields , but complicated field theoretical equations are needed to show how quantum probabilities lead to classical well defined fields. See motls.blogspot.com/2011/11/…
Apr 25, 2021 at 17:23 comment added Mercury @trula The answer to this is that at the very first instant of the crash (in infinitesimal time) the force (however big) changes only the direction of the velocity. After that the velocity is not perp. and the force can increase it. That's why I am asking about a photon and its 0 time of action and 0 force after the action. (example is the Moon and gravity).
Apr 25, 2021 at 17:14 comment added Mercury @annav Does your remark mean that work in Cl.Ph. is not correctly defined from point of view of QP? As far as I know the classical quantities are mean values in time of the 'real' quantum quantities. But one can use a coherent radiation (e.g. many photons) and get a close to the quantum quantity (e.g. there will be work in a classical sense). The 'force' powering this 'work' will be perpendicular to the body (to be more close to a perpendicular surface one can use a quality crystal grid).
Apr 25, 2021 at 5:54 comment added anna v thinking in terms of classical mechanics with quantum mechanical entities (work is a classical mechanics variable) as are photons and atoms leads to confusions. Quantum mechanics and the four vectors of special relativity had to be discovered in order to explain atomic behavior.. The photon with energy E and three momentum p transfers its dp/dt to the atom and the four vector algebra defines the kinematics
Apr 24, 2021 at 23:36 history edited Dale CC BY-SA 4.0
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Apr 24, 2021 at 23:35 answer added Dale timeline score: 1
Apr 24, 2021 at 20:28 comment added trula you say " it is postulated that a perpendicular force can not do work." consider two cars crashing with perpendicular velocity on a crossing, No damage?
Apr 24, 2021 at 20:00 history asked Mercury CC BY-SA 4.0