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I have seen Hz defined in different ways, if $$\Omega = 1 Hz = 1\frac{cycle}{s} $$ Here $ 1 cycle = $ a full turn of the rotor = $2\pi$

If I wish to express this a rpm:

By definition $ 1 rev = $ a full turn of the rotor = $2\pi$

So, $$1Hz = 1\frac{cycle}{s} = 1\frac{rev}{s} = 1\frac{rev}{s} \cdot\frac{60s}{min} = 60 rpm$$ I wonder if this is true because I saw a different transformation from Hz to rpm: $$𝜔 = 24𝐻𝑧 = 24 Hz ∗(\frac{1}{𝑠}\frac{𝑟𝑒𝑣}{2𝜋}\frac{60𝑠}{𝑚𝑖𝑛}) = 231𝑟𝑝𝑚$$ He has that "random" pi factor. In here, omega is the angular speed of the rotor, so 24 turns per second.

I have seen Hz defined in different ways, if $$\Omega = 1 \ \text{Hz} = 1\frac{\text{cycle}}{\text{s}} $$ Here $1 \ \text{cycle} =$ a full turn of the rotor $= 2\pi$

If I wish to express this a rpm:

By definition $ 1 \ \text{rev} = $ a full turn of the rotor = $2\pi$

So, $$1 \ \text{Hz} = 1\frac{\text{cycle}}{\text{s}} = 1\frac{\text{rev}}{\text{s}} = 1\frac{\text{rev}}{\text{s}} \cdot \frac{60 \ \text{s}}{\text{min}} = 60 \ \text{rpm}$$ I wonder if this is true because I saw a different transformation from Hz to rpm: $$\omega = 24 \ \text{Hz} = 24 \ \text{Hz} \left( \frac{1}{s}\frac{\text{rev}}{2\pi}\frac{60 \ \text{s}}{\text{min}} \right) = 231 \ \text{rpm}$$ He has that "random" pi factor. In here, omega is the angular speed of the rotor, so 24 turns per second.

I have seen Hz defined in different ways, if $$\Omega = 1 Hz = 1\frac{cycle}{s} $$ Here $ 1 cycle = $ a full turn of the rotor = $2\pi$

If I wish to express this a rpm:

By definition $ 1 rev = $ a full turn of the rotor = $2\pi$

So, $$1Hz = 1\frac{cycle}{s} = 1\frac{rev}{s} = 1\frac{rev}{s} \cdot\frac{60s}{min} = 60 rpm$$ I wonder if this is true because I saw a different transformation to rpm ?

I have seen Hz defined in different ways, if $$\Omega = 1 Hz = 1\frac{cycle}{s} $$ Here $ 1 cycle = $ a full turn of the rotor = $2\pi$

If I wish to express this a rpm:

By definition $ 1 rev = $ a full turn of the rotor = $2\pi$

So, $$1Hz = 1\frac{cycle}{s} = 1\frac{rev}{s} = 1\frac{rev}{s} \cdot\frac{60s}{min} = 60 rpm$$ I wonder if this is true because I saw a different transformation from Hz to rpm: $$𝜔 = 24𝐻𝑧 = 24 Hz ∗(\frac{1}{𝑠}\frac{𝑟𝑒𝑣}{2𝜋}\frac{60𝑠}{𝑚𝑖𝑛}) = 231𝑟𝑝𝑚$$ He has that "random" pi factor. In here, omega is the angular speed of the rotor, so 24 turns per second.

Say I have a rotation rate of: $$\Omega = 1 Hz = 1\frac{cycle}{s} $$ Here $ 1 cycle = $ a full turn of the rotor = $2\pi$

If I wish to express this a rpm:

By definition $ 1 rev = $ a full turn of the rotor = $2\pi$

So, $$1Hz = 1\frac{cycle}{s} = 1\frac{rev}{s} = 1\frac{rev}{s} \cdot\frac{60s}{min} = 60 rpm$$

Is this reasoning correct?

I have seen Hz defined in different ways, if $$\Omega = 1 Hz = 1\frac{cycle}{s} $$ Here $ 1 cycle = $ a full turn of the rotor = $2\pi$

If I wish to express this a rpm:

By definition $ 1 rev = $ a full turn of the rotor = $2\pi$

So, $$1Hz = 1\frac{cycle}{s} = 1\frac{rev}{s} = 1\frac{rev}{s} \cdot\frac{60s}{min} = 60 rpm$$ I wonder if this is true because I saw a different transformation to rpm ?