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Post Closed as "Duplicate" by ProfRob, Qmechanic♦
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Qmechanic ♦
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where Where does the energy vanish in wave interference?

In my physics textbook there is a chapter on waves. Now there is a topic on interference. I don't understand why I get additional energy there. Suppose two waves presented as $Y_1=3\sin(\omega t)$ and $Y_2=3\sin(\omega t)$ now if I add their energy I get total $\text{intensity}=\frac{k}{2}\cdot 3^2+\frac{k}{2}\cdot 3^2$. but again these waves are superimposed if F see this from another viewpoint then I get total $\text{amplitude}=6$. So $\text{energy}=\frac{k}{2}\cdot 6^2$ where $k$ is constant. So where does the energy go  ? and I tried Googling it, there t found that it's simply rearrangement of energy. But I think that doesn't explain this. And terribly sorry for my bad english

where does the energy vanish in wave interference?

In my physics textbook there is a chapter on waves. Now there is a topic on interference. I don't understand why I get additional energy there. Suppose two waves presented as $Y_1=3\sin(\omega t)$ and $Y_2=3\sin(\omega t)$ now if I add their energy I get total $\text{intensity}=\frac{k}{2}\cdot 3^2+\frac{k}{2}\cdot 3^2$. but again these waves are superimposed if F see this from another viewpoint then I get total $\text{amplitude}=6$. So $\text{energy}=\frac{k}{2}\cdot 6^2$ where $k$ is constant. So where does the energy go  ? and I tried Googling it, there t found that it's simply rearrangement of energy. But I think that doesn't explain this. And terribly sorry for my bad english

Where does the energy vanish in wave interference?

In my physics textbook there is a chapter on waves. Now there is a topic on interference. I don't understand why I get additional energy there. Suppose two waves presented as $Y_1=3\sin(\omega t)$ and $Y_2=3\sin(\omega t)$ now if I add their energy I get total $\text{intensity}=\frac{k}{2}\cdot 3^2+\frac{k}{2}\cdot 3^2$. but again these waves are superimposed if F see this from another viewpoint then I get total $\text{amplitude}=6$. So $\text{energy}=\frac{k}{2}\cdot 6^2$ where $k$ is constant. So where does the energy go? and I tried Googling it, there t found that it's simply rearrangement of energy. But I think that doesn't explain this. And terribly sorry for my bad english

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Tekton_infernus
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where does the energy vanish in wave interference?

In my physics textbook there is a chapter on waves. Now there is a topic on interference. I don't understand why I get additional energy there. Suppose two waves presented as $Y_1=3\sin(\omega t)$ and $Y_2=3\sin(\omega t)$ now if I add their energy I get total $\text{intensity}=\frac{k}{2}\cdot 3^2+\frac{k}{2}\cdot 3^2$. but again these waves are superimposed if F see this from another viewpoint then I get total $\text{amplitude}=6$. So $\text{energy}=\frac{k}{2}\cdot 6^2$ where $k$ is constant. So where does the energy go ? and I tried Googling it, there t found that it's simply rearrangement of energy. But I think that doesn't explain this. And terribly sorry for my bad english