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NedSunshine
NedSunshine
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Context: I'm creating a simulated VR billiard game and trying to get the physics as realistic as possible. I have a cue ball being hit with a cue across a surface with accurate friction values calculated from real-world trials.

Question: According to this source:

Angular velocity equals of a moving ball: $$w = \frac{5g}{2r}{ μ_k t}$$ If we look at the rolling phase after sliding, does this mean that no matter how hard you hit the ball, the angular velocity will always be the same (assume force acts on the center) as it is dependent on the radius and gravity only?

Hierrezuelo, J. and Carnero, C., 1995. Sliding and rolling: the physics of a rolling ball. Physics Education, 30(3), p.177.

Context: I'm creating a simulated VR billiard game and trying to get the physics as realistic as possible. I have a cue ball being hit with a cue across a surface with accurate friction values calculated from real-world trials.

Question: According to this source:

Angular velocity equals of a moving ball: $$w = \frac{5g}{2r}{ μ_k t}$$ If we look at the rolling phase after sliding, does this mean that no matter how hard you hit the ball, the angular velocity will always be the same (assume force acts on the center) as it is dependent on the radius and gravity only?

Context: I'm creating a simulated VR billiard game and trying to get the physics as realistic as possible. I have a cue ball being hit with a cue across a surface with accurate friction values calculated from real-world trials.

Question: According to this source:

Angular velocity equals of a moving ball: $$w = \frac{5g}{2r}{ μ_k t}$$ If we look at the rolling phase after sliding, does this mean that no matter how hard you hit the ball, the angular velocity will always be the same (assume force acts on the center) as it is dependent on the radius and gravity only?

Hierrezuelo, J. and Carnero, C., 1995. Sliding and rolling: the physics of a rolling ball. Physics Education, 30(3), p.177.

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NedSunshine
NedSunshine
  • 3
  • 2

Context: I'm creating a simulated VR billiard game and trying to get the physics as realistic as possible. I have a cue ball being hit with a cue across a surface with accurate friction values calculated from real-world trials.

Question: According to this source:

Angular accelerationvelocity equals of a moving ball: $$w = \frac{5g}{2r}{ μ_k t}$$ If we look at the rolling phase after sliding, does this mean that no matter how hard you hit the ball, the angular accelerationvelocity will always be the same (assume force acts on the center) as it is dependent on the radius and gravity only?

Context: I'm creating a simulated VR billiard game and trying to get the physics as realistic as possible. I have a cue ball being hit with a cue across a surface with accurate friction values calculated from real-world trials.

Question: According to this source:

Angular acceleration equals of a moving ball: $$w = \frac{5g}{2r}{ μ_k t}$$ If we look at the rolling phase after sliding, does this mean that no matter how hard you hit the ball, the angular acceleration will always be the same (assume force acts on the center) as it is dependent on the radius and gravity only?

Context: I'm creating a simulated VR billiard game and trying to get the physics as realistic as possible. I have a cue ball being hit with a cue across a surface with accurate friction values calculated from real-world trials.

Question: According to this source:

Angular velocity equals of a moving ball: $$w = \frac{5g}{2r}{ μ_k t}$$ If we look at the rolling phase after sliding, does this mean that no matter how hard you hit the ball, the angular velocity will always be the same (assume force acts on the center) as it is dependent on the radius and gravity only?

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NedSunshine
NedSunshine
  • 3
  • 2

Is angular velocity independent of initial force causing the motion?

Context: I'm creating a simulated VR billiard game and trying to get the physics as realistic as possible. I have a cue ball being hit with a cue across a surface with accurate friction values calculated from real-world trials.

Question: According to this source:

Angular acceleration equals of a moving ball: $$w = \frac{5g}{2r}{ μ_k t}$$ If we look at the rolling phase after sliding, does this mean that no matter how hard you hit the ball, the angular acceleration will always be the same (assume force acts on the center) as it is dependent on the radius and gravity only?