I have a question about the spontaneous symmetry breaking (SSB) and its effect on the group symmetries of the Standard Model.
If I understand correctly, before SSB (at high temperatures/energies) the initial symmetry was given by:
$$SU(3)\times SU(2)_{L}\times U(1)_{Y}$$$$SU(3)_C\times SU(2)_{L}\times U(1)_{Y}$$ where $SU(2)_{L}\times U(1)_{Y}$ symmetry group describes the electroweak interactions.
After SSB the symmetry broke into: $$SU(3)\times U(1)_{Q}$$$$SU(3)_C\times U(1)_{Q}$$
And this is actually what we observe now at room temperature.
My question is the following: Since $SU(3)$$SU(3)_C$ describes the strong interactions, and $U(1)_{Q}$ describes the electromagnetic interactions, (why) isn't there a symmetry group describing the weak interaction (after SSB - so "decoupled" from the electromagnetic interaction)?
EDIT:
Perhaps it would be useful to say what made me ask this question. I encountered the following piece of information on various references:
The electroweak symmetry is spontaneously broken to the $U(1)_{Q}$ symmetry, $$SU(3)\times SU(2)_{L}\times U(1)_{Y}\rightarrow SU(3)\times U(1)_{Q}$$$$SU(3)_C\times SU(2)_{L}\times U(1)_{Y}\rightarrow SU(3)_C\times U(1)_{Q}$$ And I somehow have the feeling that the $SU(2)_{L}$ group is for some reason left out of discussion (as if it doesn't exist anymore).