I have a question about the spontaneous symmetry breaking (SSB) and its effect on the group symmetries of the Standard Model.

If I understand correctly, before SSB (at high temperatures/energies) the *initial* symmetry was given by: 

$$SU(3)_C\times SU(2)_{L}\times U(1)_{Y}$$
where $SU(2)_{L}\times U(1)_{Y}$ symmetry group describes the electroweak interactions.

After SSB the symmetry broke into:
$$SU(3)_C\times U(1)_{Q}$$

And this is actually what we observe now *at room temperature.*

My question is the following: Since $SU(3)_C$ describes the strong interactions, and $U(1)_{Q}$ describes the electromagnetic interactions, (why) isn't there a symmetry group describing the weak interaction (after SSB - so "decoupled" from the electromagnetic interaction)?

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**EDIT:**

Perhaps it would be useful to say what made me ask this question. I encountered the following piece of information on various references:

The electroweak symmetry is spontaneously broken to the $U(1)_{Q}$ symmetry,
$$SU(3)_C\times SU(2)_{L}\times U(1)_{Y}\rightarrow SU(3)_C\times U(1)_{Q}$$
And I somehow have the feeling that the $SU(2)_{L}$ group is for some reason left out of discussion (as if it doesn't exist anymore).

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