Timeline for In what sense are boron and carbon the simplest examples of degenerate atomic ground states?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| May 4, 2020 at 23:34 | comment | added | mike stone | Mmmm. As Emilio says,you can't really have exactly degenerate states unless some symmetry forbids the coupling. | |
| May 4, 2020 at 19:30 | comment | added | Emilio Pisanty | Boron and carbon obviously have hyperfine splitting. Why would you think (or claim) that they don't? | |
| May 4, 2020 at 17:51 | comment | added | Ruslan | Actually, the answer linked doesn't elaborate about the precision to which boron and carbon and other atoms have the same-energy $m=\mathrm{var}$ states. It might appear that they do have hyperfine splitting, but that answer simply was on a cruder approximation. | |
| May 4, 2020 at 17:01 | comment | added | Solidification | Boron and carbon really do not have hyperfine splitting of the ground state? | |
| May 4, 2020 at 16:16 | history | answered | mike stone | CC BY-SA 4.0 |