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Qmechanic
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stresses Stresses in asteroid during close flyby of asteroids

The acceleration of an asteroid (such as 2012DA14) as it approaches earth is proportional to the reciprocal of distance (r)$r$ from earth center, squared. the derivative of the acceleration, or jerk, is then proportional to the cube of the reciprocal of distance r$r$, and the speed (r')$v$. Thus the jerk is rapidly increasing as the asteroid approaches. WillWill the asteroid experience stresses from the jerk that could possibly cause it to break up?

stresses in close flyby of asteroids

The acceleration of an asteroid (such as 2012DA14) as it approaches earth is proportional to the reciprocal of distance (r) from earth center, squared. the derivative of the acceleration, or jerk, is then proportional to the cube of the reciprocal of distance r, and the speed (r'). Thus the jerk is rapidly increasing as the asteroid approaches. Will the asteroid experience stresses from the jerk that could possibly cause it to break up?

Stresses in asteroid during close flyby

The acceleration of an asteroid (such as 2012DA14) as it approaches earth is proportional to the reciprocal of distance $r$ from earth center, squared. the derivative of the acceleration, or jerk, is then proportional to the cube of the reciprocal of distance $r$, and the speed $v$. Thus the jerk is rapidly increasing as the asteroid approaches. Will the asteroid experience stresses from the jerk that could possibly cause it to break up?

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Dave
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stresses in close flyby of asteroids

The acceleration of an asteroid (such as 2012DA14) as it approaches earth is proportional to the reciprocal of distance (r) from earth center, squared. the derivative of the acceleration, or jerk, is then proportional to the cube of the reciprocal of distance r, and the speed (r'). Thus the jerk is rapidly increasing as the asteroid approaches. Will the asteroid experience stresses from the jerk that could possibly cause it to break up?