Skip to main content
Improved text
Source Link
Sebastiano
  • 2.6k
  • 4
  • 24
  • 48

Commutators The use of the commutators in quantum mechanics: explanations

To have a prove of the Heisenberg uncertainty principleConsidering that I've never studied quantum mechanics before I have need to understand the operator commutator. My starting pointstart is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$. I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ where $p_x$ is the momentum on $x-$ axis.

Are very appreciated simple books where I can find very simple operations with these commutators because I have never studied quantum mechanics.

I thank in advance anyone who could help me to understand the commutators.

Commutators in quantum mechanics

To have a prove of the Heisenberg uncertainty principle I have need to understand the operator commutator. My starting point is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$. I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ where $p_x$ is the momentum on $x-$ axis.

Are very appreciated simple books where I can find very simple operations with these commutators because I have never studied quantum mechanics.

I thank in advance anyone who could help me to understand the commutators.

The use of the commutators in quantum mechanics: explanations

Considering that I've never studied quantum mechanics before I have need to understand the operator commutator. My start is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$. I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ where $p_x$ is the momentum on $x-$ axis.

added 32 characters in body; edited title
Source Link
Sebastiano
  • 2.6k
  • 4
  • 24
  • 48

How to understand commutation operations Commutators in quantum mechanics?

To be able tohave a prove of the Heisenberg uncertainty principle I have need to understand the operator commutator. My starting point is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$.

  I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ where $p_x$ is the momentum on $x-$ axis.

Are very appreciated simple books where I can find very simple operations with these commutators because I have never studied quantum mechanics.

I thank in advance anyone who could help me to understand the commutators.

How to understand commutation operations in quantum mechanics?

To be able to prove the Heisenberg uncertainty principle I have need to understand the operator commutator. My starting point is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$.

  I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ $p_x$ is the momentum on $x-$ axis.

Are very appreciated simple books where I can find very simple operations with these commutators because I have never studied quantum mechanics.

I thank in advance anyone who could help me.

Commutators in quantum mechanics

To have a prove of the Heisenberg uncertainty principle I have need to understand the operator commutator. My starting point is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$. I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ where $p_x$ is the momentum on $x-$ axis.

Are very appreciated simple books where I can find very simple operations with these commutators because I have never studied quantum mechanics.

I thank in advance anyone who could help me to understand the commutators.

edited body
Source Link

To be able to prove the HeisembergHeisenberg uncertainty principle I have need to understand the operator commutator. My starting point is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$.

I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ $p_x$ is the momentum on $x-$ axis.

Are very appreciated simple books where I can find very simple operations with these commutators because I have never studied quantum mechanics.

I thank in advance anyone who could help me.

To be able to prove the Heisemberg uncertainty principle I have need to understand the operator commutator. My starting point is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$.

I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ $p_x$ is the momentum on $x-$ axis.

Are very appreciated simple books where I can find very simple operations with these commutators because I have never studied quantum mechanics.

I thank in advance anyone who could help me.

To be able to prove the Heisenberg uncertainty principle I have need to understand the operator commutator. My starting point is: $[A,B]=AB-BA \tag{a}$

Now, why must be

$$\left[\frac{\partial }{\partial x},x\right]\stackrel{?}{=}1 \tag{1}$$ I have thought, from the rule (a),

This identity $$\left[x,\frac{\partial }{\partial x}\right]=-1 \tag{2}$$ is easy because $[A,B]=-[B,A]$.

I have not understood, also, (3) and (4) $$\left[i\hslash\frac {\partial}{\partial x},x\right]=i\hslash \tag{3}$$

$$[p_x,x]=i\hslash \tag{4}$$ $p_x$ is the momentum on $x-$ axis.

Are very appreciated simple books where I can find very simple operations with these commutators because I have never studied quantum mechanics.

I thank in advance anyone who could help me.

Edit totally the question
Source Link
Sebastiano
  • 2.6k
  • 4
  • 24
  • 48
Loading
I hope that my improved text now it is clear.
Source Link
Sebastiano
  • 2.6k
  • 4
  • 24
  • 48
Loading
deleted 84 characters in body
Source Link
Sebastiano
  • 2.6k
  • 4
  • 24
  • 48
Loading
edited tags
Link
Qmechanic
  • 213.1k
  • 48
  • 590
  • 2.3k
Loading
edited tags
Link
BioPhysicist
  • 58.6k
  • 19
  • 116
  • 193
Loading
Changed classical mechanics tag to quantum mechanics, removed 'hamiltonian formalism' tag, removed 'anti-commutator' tag.
Source Link
Sebastiano
  • 2.6k
  • 4
  • 24
  • 48
Loading
added 39 characters in body
Source Link
Sebastiano
  • 2.6k
  • 4
  • 24
  • 48
Loading
Source Link
Sebastiano
  • 2.6k
  • 4
  • 24
  • 48
Loading