Timeline for Horizontal velocity component on a periodic circular motion

11 events

when toggle format	what		by	license	comment
Apr 10, 2019 at 12:56	comment	added	Karsun		@gandalf61 thanks, your intuition is right.
Apr 10, 2019 at 11:30	vote	accept	Karsun
Apr 10, 2019 at 11:11	comment	added	gandalf61		If $d$ is fixed then $q'$ has a radial veloctiy $v_r$ as well as a tangential velocity $v_t$. So it is no longer true that $v_x=v_t\cos\theta$. Instead $v_x=v_t\cos\theta + v_r\sin\theta$ and your second method gives the correct answer.
Apr 10, 2019 at 11:10	answer	added	noah		timeline score: 0
Apr 10, 2019 at 10:52	history	edited	Karsun	CC BY-SA 4.0	added 23 characters in body
Apr 10, 2019 at 10:50	comment	added	Karsun		@gandalf61 I think I forgot to mention that $d$ is a fixed distance while $d'$ is not.
Apr 10, 2019 at 10:32	comment	added	gandalf61		In your second method remember that $d$ and $\theta$ are both functions of time, so $\frac{ds}{dt} = \frac{dd}{dt}\tan \theta + d(1+\tan^2 \theta)\frac{d\theta}{dt}$. I think you have omitted the first term.
Apr 10, 2019 at 9:20	history	edited	Karsun	CC BY-SA 4.0	deleted 38 characters in body
Apr 10, 2019 at 9:15	history	edited	Karsun	CC BY-SA 4.0	deleted 38 characters in body
Apr 10, 2019 at 9:10	review	First posts
Apr 10, 2019 at 9:28
Apr 10, 2019 at 9:09	history	asked	Karsun	CC BY-SA 4.0