Skip to main content

Timeline for Transformation of $4-$velocity

Current License: CC BY-SA 4.0

7 events
when toggle format what by license comment
Apr 2, 2019 at 9:17 vote accept M.N.Raia
Apr 2, 2019 at 6:20 answer added Voulkos timeline score: 3
Feb 16, 2019 at 6:02 history edited Qmechanic CC BY-SA 4.0
added 16 characters in body; edited tags; edited tags
Feb 16, 2019 at 0:54 history edited M.N.Raia CC BY-SA 4.0
added 1 character in body
Feb 15, 2019 at 17:56 comment added G. Smith Equation (1) is missing a prime on the left hand side.
Feb 15, 2019 at 14:39 comment added Frederic Thomas You already proofed $u^{\mu}$ being a Minkowski 4-vector in eq. (8) since $u^{\mu}$ transforms like $A^{\mu}$ in eq. (4) (taking into account the definition of $\Lambda^{\mu}_\nu$ one line above). However, $v^{\mu}$ does not transform like a Minkowski 4-vector because $v'^\mu= \frac{dx^{\mu}}{dt'}$ (note the little prime) and depending on the reference system $dt =d\tau/\gamma$ or NOT. However in your equation it is simply assumed that $dt =d\tau/\gamma$ always. That's the point. (On the other hand as you already said $d\tau$ is always the same independent on the reference system).
Feb 15, 2019 at 10:17 history asked M.N.Raia CC BY-SA 4.0