Timeline for Transformation of $4-$velocity
Current License: CC BY-SA 4.0
7 events
when toggle format | what | by | license | comment | |
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Apr 2, 2019 at 9:17 | vote | accept | M.N.Raia | ||
Apr 2, 2019 at 6:20 | answer | added | Voulkos | timeline score: 3 | |
Feb 16, 2019 at 6:02 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 16 characters in body; edited tags; edited tags
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Feb 16, 2019 at 0:54 | history | edited | M.N.Raia | CC BY-SA 4.0 |
added 1 character in body
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Feb 15, 2019 at 17:56 | comment | added | G. Smith | Equation (1) is missing a prime on the left hand side. | |
Feb 15, 2019 at 14:39 | comment | added | Frederic Thomas | You already proofed $u^{\mu}$ being a Minkowski 4-vector in eq. (8) since $u^{\mu}$ transforms like $A^{\mu}$ in eq. (4) (taking into account the definition of $\Lambda^{\mu}_\nu$ one line above). However, $v^{\mu}$ does not transform like a Minkowski 4-vector because $v'^\mu= \frac{dx^{\mu}}{dt'}$ (note the little prime) and depending on the reference system $dt =d\tau/\gamma$ or NOT. However in your equation it is simply assumed that $dt =d\tau/\gamma$ always. That's the point. (On the other hand as you already said $d\tau$ is always the same independent on the reference system). | |
Feb 15, 2019 at 10:17 | history | asked | M.N.Raia | CC BY-SA 4.0 |