Skip to main content
Question Protected by Qmechanic

Let's start with kinetic energy (from los Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed $v$ is $\frac{1}{2}mv^2$.

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

$ E_a = 1/2 * 100 * 10^2 = 5000J = 5kJ$$$ E_a = 1/2 \times 100 \times 10^2 = 5000J = 5kJ$$

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

$ E_b = 10000J =1/2 * 100 *V_b^2 \implies V_b = \sqrt{10000 / (1/2 * 100)} = √200 = 14.14m/s$$$ E_b = 10000J =1/2 \times 100 \times V_b^2$$ $$\implies V_b = \sqrt{10000 / (1/2 \times 100)} = √200 = 14.14m/s$$

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, Will 5kJ of energy always produce 10m/s of relative velocity,,assuming 100kg spaceships?

If 5kJ always produces 10m/s, Why does the second 5kJ only produce 4.1m/s? What is going on here?

Let's start with kinetic energy (from los Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed $v$ is $\frac{1}{2}mv^2$.

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

$ E_a = 1/2 * 100 * 10^2 = 5000J = 5kJ$

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

$ E_b = 10000J =1/2 * 100 *V_b^2 \implies V_b = \sqrt{10000 / (1/2 * 100)} = √200 = 14.14m/s$

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, Will 5kJ of energy always produce 10m/s of relative velocity,,assuming 100kg spaceships?

If 5kJ always produces 10m/s, Why does the second 5kJ only produce 4.1m/s? What is going on here?

Let's start with kinetic energy (from los Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed $v$ is $\frac{1}{2}mv^2$.

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

$$ E_a = 1/2 \times 100 \times 10^2 = 5000J = 5kJ$$

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

$$ E_b = 10000J =1/2 \times 100 \times V_b^2$$ $$\implies V_b = \sqrt{10000 / (1/2 \times 100)} = √200 = 14.14m/s$$

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, Will 5kJ of energy always produce 10m/s of relative velocity,,assuming 100kg spaceships?

If 5kJ always produces 10m/s, Why does the second 5kJ only produce 4.1m/s? What is going on here?

Equations are written in latex.some corrections are done.
Source Link

Let's start with kinetic energy (from los Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed $v$ is $\frac{1}{2}mv^2$.

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

E_a = ½ * 100 * 10²
    = 5000J = 5kJ

$ E_a = 1/2 * 100 * 10^2 = 5000J = 5kJ$

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

E_b = 10000J = ½ * 100 * v_b²
v_b = √(10000 / (½ * 100))
    = √200
    = 14.14m/s

$ E_b = 10000J =1/2 * 100 *V_b^2 \implies V_b = \sqrt{10000 / (1/2 * 100)} = √200 = 14.14m/s$

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, what happens? Assuming 100kg spaceships, willWill 5kJ of energy always produce 10m/s of relative velocity,,assuming 100kg spaceships? 

If 5kJ always produces 10m/s, whyWhy does the second 5kJ only produce 4.1m/s? What is going on here?

Let's start with kinetic energy (from los Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed $v$ is $\frac{1}{2}mv^2$.

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

E_a = ½ * 100 * 10²
    = 5000J = 5kJ

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

E_b = 10000J = ½ * 100 * v_b²
v_b = √(10000 / (½ * 100))
    = √200
    = 14.14m/s

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, what happens? Assuming 100kg spaceships, will 5kJ of energy always produce 10m/s of relative velocity? If 5kJ always produces 10m/s, why does the second 5kJ only produce 4.1m/s? What is going on here?

Let's start with kinetic energy (from los Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed $v$ is $\frac{1}{2}mv^2$.

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

$ E_a = 1/2 * 100 * 10^2 = 5000J = 5kJ$

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

$ E_b = 10000J =1/2 * 100 *V_b^2 \implies V_b = \sqrt{10000 / (1/2 * 100)} = √200 = 14.14m/s$

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, Will 5kJ of energy always produce 10m/s of relative velocity,,assuming 100kg spaceships? 

If 5kJ always produces 10m/s, Why does the second 5kJ only produce 4.1m/s? What is going on here?

added link; retagged;
Source Link
Qmechanic
  • 213.1k
  • 48
  • 590
  • 2.3k

Let's start with kinetic energy (from los Wikipediaslos Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed v is ½mv².The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed $v$ is $\frac{1}{2}mv^2$.

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

E_a = ½ * 100 * 10²
    = 5000J = 5kJ

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

E_b = 10000J = ½ * 100 * v_b²
v_b = √(10000 / (½ * 100))
    = √200
    = 14.14m/s

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, what happens? Assuming 100kg spaceships, will 5kJ of energy always produce 10m/s of relative velocity? If 5kJ always produces 10m/s, why does the second 5kJ only produce 4.1m/s? What is going on here?

Let's start with kinetic energy (from los Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed v is ½mv².

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

E_a = ½ * 100 * 10²
    = 5000J = 5kJ

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

E_b = 10000J = ½ * 100 * v_b²
v_b = √(10000 / (½ * 100))
    = √200
    = 14.14m/s

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, what happens? Assuming 100kg spaceships, will 5kJ of energy always produce 10m/s of relative velocity? If 5kJ always produces 10m/s, why does the second 5kJ only produce 4.1m/s? What is going on here?

Let's start with kinetic energy (from los Wikipedias)

The kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. In classical mechanics, the kinetic energy of a non-rotating object of mass m traveling at a speed $v$ is $\frac{1}{2}mv^2$.

Let's say you & your bike have mass of 100kgs, then your kinetic energy at 10m/s would be

E_a = ½ * 100 * 10²
    = 5000J = 5kJ

If you apply another 5kJ of energy, you don't get to 20m/s though, you only get to:

E_b = 10000J = ½ * 100 * v_b²
v_b = √(10000 / (½ * 100))
    = √200
    = 14.14m/s

Let's say you and a buddy are both coasting along at 10m/s though, from their perspective you've just burned 5kJ but only accelerated 4.1m/s, even though you seemed stationary.

Imagine you and your mate are in space drifting along together, at an unknown speed. Your mate fires his burners and accelerates away from you. There's a big screen on his ship showing how many joules of energy he just burned, and you can measure his resulting relative velocity just fine.

The question is, what happens? Assuming 100kg spaceships, will 5kJ of energy always produce 10m/s of relative velocity? If 5kJ always produces 10m/s, why does the second 5kJ only produce 4.1m/s? What is going on here?

Source Link
geelen
  • 421
  • 1
  • 4
  • 3
Loading