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David Z
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How to express Expressing average velocity in terms of acceleration

Average velocity is usually expressed as the displacement divided by the time. For example,

V_avg= (x(t)-x_o)/t .

I $$v_{\text{avg}} = \frac{x(t)-x_0}{t}$$ I have not, however seen it expressed in terms of acceleration. Would it be incorrect to say $$v_{\text{avg}}= \bigl(a(t)-a_0\bigr)\times t$$

V_avg= (a(t)-a_0)*t.

How to express average velocity

Average velocity is usually expressed as the displacement divided by the time. For example,

V_avg= (x(t)-x_o)/t .

I have not, however seen it expressed in terms of acceleration. Would it be incorrect to say

V_avg= (a(t)-a_0)*t.

Expressing average velocity in terms of acceleration

Average velocity is usually expressed as the displacement divided by the time. For example, $$v_{\text{avg}} = \frac{x(t)-x_0}{t}$$ I have not, however seen it expressed in terms of acceleration. Would it be incorrect to say $$v_{\text{avg}}= \bigl(a(t)-a_0\bigr)\times t$$

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How to express average velocity

Average velocity is usually expressed as the displacement divided by the time. For example,

V_avg= (x(t)-x_o)/t .

I have not, however seen it expressed in terms of acceleration. Would it be incorrect to say

V_avg= (a(t)-a_0)*t.