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Qmechanic
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Kyle Kanos
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Given a position function of a particle:

r = rr^(θ) ( $$ \mathbf r=r\,\hat{\mathbf r}\left(\theta\right), $$ where r^(θ)$\hat{\mathbf r}(θ)$ is the polar unit vector)

, to find the velocity, we take the derivative which results in:

v = dr/dt = (dr/dt) r^(θ) + r(dr^(θ)/dt).$$ \mathbf v = \frac{\mathrm d\mathbf r}{\mathrm dt} = \frac{\mathrm dr}{\mathrm dt} \hat{\mathbf r}(θ) + r\frac{\mathrm d\hat{\mathbf r}(θ)}{\mathrm dt}.$$

What does each term in the velocity equation mean?

Given a position function of a particle:

r = rr^(θ) (where r^(θ) is the polar unit vector)

to find the velocity, we take the derivative which results in:

v = dr/dt = (dr/dt) r^(θ) + r(dr^(θ)/dt).

What does each term in the velocity equation mean?

Given a position function of a particle: $$ \mathbf r=r\,\hat{\mathbf r}\left(\theta\right), $$ where $\hat{\mathbf r}(θ)$ is the polar unit vector, to find the velocity, we take the derivative which results in:

$$ \mathbf v = \frac{\mathrm d\mathbf r}{\mathrm dt} = \frac{\mathrm dr}{\mathrm dt} \hat{\mathbf r}(θ) + r\frac{\mathrm d\hat{\mathbf r}(θ)}{\mathrm dt}.$$

What does each term in the velocity equation mean?

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Assistance interpreting equation

Given a position function of a particle:

r = rr^(θ) (where r^(θ) is the polar unit vector)

to find the velocity, we take the derivative which results in:

v = dr/dt = (dr/dt) r^(θ) + r(dr^(θ)/dt).

What does each term in the velocity equation mean?